solve the equation.. show work!!
1) |4x-9|= -4
2) x+1 - 2 {x+11} = 0 { }= square root symbol..since there isnt one on the keyboard!!
Thanks!
2007-08-13 16:23:39 · 6 answers · asked by sexycheerleader2009 3 in Science & Mathematics ➔ Mathematics
|4x-9|=-4
--> 4x-9=-4 and 4x-9 = 4
--> 4x-9=-4 --> 4x=5 --> x=5/4
--> 4x-9 = 4 --> 4x=-5 --> x=-5/4
x + 1 = 2 * sqrt(x+11)
(x+1)/2 = sqrt(x + 11) square both sides
(x+1)^2 / 4 = x+11
x^2 + 2x + 1 = 4x + 44
x^2 -2x - 43 = 0
use the quadratic formula to solve for x (or just plug it into your graphing calculator...)
2007-08-13 16:34:58 · answer #1 · answered by Anonymous · 0⤊ 0⤋
1) 4x - 9 = -4
x = (-4 + 9)/4
x = 5/4
2) x + 1 - 2 sqrt(x + 11) = 0
x + 1 = 2 sqrt(x + 11)
square both sides
(x + 1)^2 = 4(x + 11)
x^2 + 2x + 1 = 4x + 44
x^2 - 2x - 43 = 0
2007-08-13 23:58:54 · answer #2 · answered by ferdie 2 · 0⤊ 0⤋
1) |4x-9|= -4
There is no solution for the problem because an absolute value can not be negative.
2) x+1 = 2 â(x+11), xâ¥-1
Square both sides,
x^2+2x+1 = 4x+44
x^2-2x-43 = 0
Using quadratic formula, you can get
x = 1+2â11
2007-08-13 23:55:07 · answer #3 · answered by sahsjing 7 · 0⤊ 0⤋
1. Invalid, the absolute value of any real number is positive.
2. (use sqrt(x+11) to show sqrt rt.
Set x+1 = 2 sqrt(x+11)
Square both sides, and collect terms.
Factor or solve quadratic by formula.
2007-08-13 23:37:03 · answer #4 · answered by cattbarf 7 · 0⤊ 0⤋
the first one is no solution, an absolute value sign cannot equal a negative number
the second one i just gave up on, i couldnt figure it out, im really sorry
2007-08-13 23:48:23 · answer #5 · answered by mack7465 3 · 0⤊ 0⤋
math is for nerds.
...that's why they call them "math nerds".
2007-08-13 23:29:30 · answer #6 · answered by Jonathan H 2 · 0⤊ 2⤋