I'm stuck on 2 math problems, can someone help me?

Question

There is points A(-2,6) B (-6,5) and C (4,-3)

What is the equation in standard for of the line parallel to AB containing point C?
and
What is the equation in standard for of the line perpendicular to AB containing point C?

Answer 1

slope AB=(5-6)/(-6+2)=-1/-4=1/4

y+3=1/4 (x-4)
4y+12=x-4

answer:
-x+4y+16=0

m1.m2=-1
1/4 m=-1

m=-4
y+3=-4(x-4)
-4x+16=y+3

answer:
-4x-y+13=0