help with math hw.?

Question

solve by extracting the square roots

(r+6) squared =10

solve using the quadratic formula.

7x squared + 12x = -3

thanks!

Answer 1

Hey dear
1st
^ for power
(r+6)^2 = 10
by taking the square root for both sides and don't forget (+or-) for the root results
r+6 =(+or-) sqrt(10)
sqrt mean square root
then we will have two values for r
r1+6 = + sqrt (10)
r1 = -6 + sqrt(10)
and
r2+6 = - sqrt (10)
r2 = -6 - sqrt(10)
and 2nd
use the equation x =(-b(+ or-) square root( b^2 - 4 ac) ) / (2a)
as a=7 b=12 c=3
you will get two values for x notice that for real values the value between brackets of the square root must be positive or zero and if it's zero you will get the same number for the two roots x1 = x2
i hope this helps you
good wishs
this is my best and i hope i get 10 extra points for best answer :-)

Answer 2

Hey, sexy, use carats or double ** for powers.
(r+6)**2 = 10, Take square root to get
r+6 = sqrt(10) OR -sqrt(10)
Solve by typical math.

Get all term on one side.
7x**2 + 12x +3 = 0
Then y =(1/14)[ -(12) +/- sqrt(144-4(7)(3) )]
Simplify by simple math.

Answer 3

(r+6)^2=10
r^2 + 12r + 36 = 10
r^2 + 12r + 26 = 0

[-b +/- sqrt ( b^2 - 4ac)]/2a

= [-12 +/- sqrt (144 - 104)]/2

= [-12 +/- sqrt 40]/2

= [-12 +/- 4sqrt 10] /2

= -6 +/- 2 (sqrt10)