probability with dice??

Question

3 dice are tossed. what is the probability of getting exactly one five??

Answer 1

3 in 216

Answer 2

The probability of a dice getting 5 is 1/6, not getting 5 is 5/6.

So the probability of one dice getting 5 AND 2 dices not getting 5 is (1/6)(5/6)^2.

But it can be any one of the 3 dices that gets 5, so we have to multiply it with 3C1.

3C1* (1/6)(5/6)^2 = 25/72

Answer 3

the probability of getting a 5 shows on one of the dice is 1/6
the probability of getting a number is 5/6

1/6 * 5/6 * 5/6 = 25/216

5 N N

BUT, 5 doesn't have to be on the first dice, it can be on the second or the third dice

so there are 3 ways you can rearragne 5 N N

P = 3 * 25/216 = 25/72

Answer 4

Each die has 6 possibilities: So the probability of getting one certain number is 1/6. However, once you get one five, you have to get any of the other the other five numbers for the other two dice.
3 * (5/6)^2 * (1/6) = 75/216 = 34.72%

Answer 5

3C1(1/6)(5/6)^2 = 25/72
-------------
Ideas: This is a typical binomial probability distribution: nCkp^k(1-p)^(n-k), with p = 1/6, 1-p = 5/6, and n = 3, k = 1. 3C1 means the "5" can occur in any one of the three dice. "(1/6)" means the probability to get 5 in each dice. "5/6" means to get non 5 in each dice.

Answer 6

assuming fair dice

Let X equal the number of 5's seen
X~Bin(3,1/6)

P(X=1) = 3*11.57% = 34.71

1/6*5/6*5/6, the prob of one five times the prob of the other two not being a five = 11.57%

Answer 7

1 half. roll one dice and you have a 1/6 chance. 2 dice make that a 2/6. 3 dice make it 1/2 chance.

Answer 8

3/216

Answer 9

the probability is 3/18 or 6% maybe

Answer 10

Wow, interesting answers.... three flat guesses (all incorrect), one guy reserving the top spot so that he can post the answer there when he finally figures it out, and one poster who actually knows what he is talking about. Good answer, Rec!