Ok I really don't get this....?

Question

I did this before but I forgot to include a parenthesis:

2 x (3-(4/2 x 5 -3) - (-5) + 6 squared)=

Just the 6 is squared, not the whole problem.

Answer 1

I will do two steps for you:

2 x (3-(4/2 x 5 -3) - (-5) + 6 squared)

=

2 x (3-(4/2 x 5 -3) - (-5) + 36)

=

2 x (3-(2 x 5 -3) - (-5) + 36)

Answer 2

I'll solve the whole problem to answer you question:

2 x (3 - (4/2 x 5 - 3) - (-5) + 6²

Take this problem step by step.

First, calculate the expression in the innermost parentheses, which is:

4/2 x 5 - 3

To do this, you must remember PEMDAS, which states that you do calculations in this order:

P = Parentheses
E = Exponent
M = Multiplication
D = Division
A = Addition
S = Subtraction

So, first complete the multiplication in this expression:

4/2 x 5 - 3
= 10 - 3 <=== Multiplication First

Now subtract, because that is your only left calculation:

10 - 3
= 7

Next, complete the expression in the second parentheses (ignore the ones around the -5):

3 - 7 - (-5) + 6²

Complete the exponent first:

3 - 7 - (-5) + 6²
= 3 - 7 - (-5) + 36

Now, add and subtract:

3 - 7 - (-5) + 36
= 3 - 7 + 41
= 44 - 7
= 37

Now, multiply this by two to obtain your answer:

2 * 37
= 74

This is your answer: 74.

Hope this helps!

Answer 3

Start with the inside parentheses and remember the order of operations: exponents, multiply/divide, add/subtract. There seems to be a missing parenthesis.

Assuming it's this:
2 x (3-(4/2 x 5 -3)) - (-5) + 36
2 x (3-(10 -3)) - (-5) + 36
2 x (3-17) - (-5) + 36
2 x (-14) - (-5) + 36
-28 - (-5) + 36
-23 + 36
+13

Answer 4

2 x (3 - (4/2 x 5 - 3) - (-5) + 6^2)

= 2 x (3 - (2 x 5 - 3) + 5 + 36) {note 4/2 = 2, -(-5) = +5, 6^2 = 36)

= 2 x (3 - (10 - 3) + 41) {note 2x5=10}

= 2 x (3 - 7 + 41)

= 2 x (- 4 + 41)

= 2 x (37)

= 74

Answer 5

74 i think