Math homework problem?

Question

Find an equation of the circle with center at
(-3, 5) that is tangent to the y-axis in the form of (x-A)^2+(y-B)^2=C where are constants.

A=_____
B=_____
C=_____

Answer 1

so your circle has a center of -3,5
if it is tangent to the y-axis this means that
it touches the y-axis and is perpendicular to it
so if you just imagine a circle that's touching the y-axis
it has a radius of 3.
Because the center of the circle is only 3 units away from the y-axis.

So in the equation form (x-a)^2 + (y-b)^2 = c
(a, b ) is the center of your circle
and "c" is the square of your radius.
so since your radius is 3, c = 9

your equation that you are looking for is

(x+3)^2 - (y-5) ^ 2 = 9

Good luck!

Answer 2

A = -3
B = 5
C = 5^2 = 25 (i.e the radius is 3, the distance between the y-intercept and the center)

So the equation is:(x + 3)^2+(y - 5)^2 = 9

I was wrong. Give the vote to the answer below.