ln(1/2)=ln1-ln2.
e^0=1, so ln1=0
0-ln2=-ln2
2007-08-13 13:50:11
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answer #1
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answered by Anonymous
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ln(1/2)=ln1-ln2=0-ln(2)=-ln(2) ANS
2007-08-13 13:51:26
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answer #2
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answered by Anonymous
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ln(1/2)=ln(1)-ln(2) - ln is to the base e.
Use a logarithmic table to find the exact value.
2007-08-13 14:10:23
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answer #3
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answered by cidyah 7
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Is this for Mentillo? By the way, the answer is ln (0.5), or -.693147
2007-08-13 13:50:06
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answer #4
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answered by Dilbert 2
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ln(1/2)=ln1-ln2= - ln2
Saludos.
2007-08-13 13:48:12
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answer #5
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answered by lou h 7
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That's log 1 - log 2 = -log 2.
In general log(1/x) = -log x.
2007-08-13 15:20:21
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answer #6
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answered by steiner1745 7
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