Math question, please help?

Question

if a single die (number cube) is rolled 300 times, how many times is a number greater than 3 expected to come up?

you don't have to give me the answer, just please tell me how to do it?

this is a different kind of question but i still don't know what to do....'if a single die is rolled 150 times, how many times is the number 3 expected to come up?

Answer 1

There are three numbers greater than 3 (4, 5, 6) on a die, and three numbers less than or equal to 3 (1, 2, 3). Three out of six possibilities is a probability of three sixths (3/6), normalized to one half. This means that no matter how many times you roll the die, half those rolls are expected to result in a number greater than 3 to come up. For 300 rolls, you would expect 150 (half of 300) to be greater than 3.

Answer 2

On a die, there are 6 sides, with 6 numbers (1,2,3,4,5,6). The chances that any number comes up is the same for all numbers. The numbers greater than 3 are only 3, half the total numbers on the die (4, 5, 6).
So if you rolled 300 times, you would expect half of them to be over 3.
Thats 150

Answer 3

The way I did this was to solve a simpler problem first. Lets say you roll ONE die. There is a 1/2 chance that a number greater than 3 will come up. Ok, so now you know that the probablility is 1/2. Now, what is 1/2 of 1? 1/2. Then you go to the real problem. Because you've already figured out half of the problem by solving the simpler problem. Now, all you have to do is take 1/2 of 300 which is 150.

Answer 4

As already stated, one half of the rolls could be expected to be greater than 3.

The possibility of any single number coming up is 1 in 6 for each roll. In 150 rolls you could expect 25 "3's". However, the rules for this type of event require really large numbers of attempts and can never be expected to show exact results. You might get 30 "3's" in 60 tries and then not see another "3" for 200 tries.

Answer 5

There are 6 sides to a die. The sides with numbers greater than 3 are {4,5,6} . The number of sides less than and equal
to 3 are {1,2,3}. Each time the die is rolled, each side has an equal chance to come up. The sides {4,5,6} have the same chance as the sides {1,2,3}. In fact, the sides {4,5,6} are 1/2 the number of total sides. They have a 50% chance of coming up. So if the die is rolled 300 times, 300 * 0.5 = 150.
If the die is rolled 150 times; 150 * 0.5 = 75
Hope this help.

Answer 6

p(number>3) = 1/2 (4,5,6). So assuming an honest die and indepedent rolls, 300 x 1/2 = 150.

Answer 7

its easy! this is dealing with probability! a cube has six faces for the numbers. so, if there are six numbers and 4,5,6 are greater than 3 that means 3/6 of the time the cube will show number greater than 3. Now u times 3/6 by 300/300 and presto!

Answer 8

Numbers > 3 are 4 , 5 and 6
P(4 , 5 or 6) = 1 / 2
From 300 throws expect 4,5 or 6 to occur 150 times.

Answer 9

You are talking about probability .
there are different possibility for this question
1)the chance of having 4,5,6 for each roll is 0.5
if your experience is about 300 times the probability of
having 4,5,6 is very close to 0.5
2)if you looking to have all of your tosses come 4 or 5 or 6 the probability is (0.5)^300

Answer 10

It is assumed that numbering will be between 1 and 6. Chance ratio between 3 and below and between 4 and above is 1 is to 1. Chances then would 50:50.

300 times * 50% = 150 times.