1) 2x^2 / x^3
2) sqaure root (then inside that) x^4
3) 2x + 4 / 2
2007-08-13 11:06:58 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
1. 2x^2/x^3= 2x^2/(x^2*x) = 2/x
2. sqrt(x^4) = sqrt(x^2*x^2) = sqrtx^2 sqrt(x^2) = x*x = x^2
3. you mean (2x+4)/2
2(x+2)/2 = x+2
2007-08-13 11:11:52 · answer #1 · answered by Helper 6 · 0⤊ 0⤋
1) 2x^2 / x^3 = 2/x because x^2/x^3 = 1/x
2) sqaure root (then inside that) x^4
= (x^4)^1/2 = x^(4*1/2) = x^2
3) (2x + 4) / 2
= 2(x+2)/2 = x=2
2007-08-13 18:16:07 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
1) 2/x : x^2/x^3 = x
2) x^2: sqrt(x^4) = x^(4/2) = x^2
3 2x + (4/2) = 2x + 2
2007-08-13 18:12:09 · answer #3 · answered by Edgar Greenberg 5 · 0⤊ 0⤋
1) divide top and bottom by x^2:
2/x
2) +/-x^2 (x^2 or -x^2)
3) (2x+4)/2 factor a 2 out of the numerator:
=2(x+2)/2 the 2's cancel:
=x+2
2007-08-13 18:11:17 · answer #4 · answered by Larry C 3 · 0⤊ 0⤋
1.) 2/x
2.)x^2
3.) didn't know if you meant 2x+4/2 or (2x+4)/2. so here's the answer to both:
2x+4/2= 2x+2
(2x+4)/2= x+2
math is fun!!
2007-08-13 18:16:37 · answer #5 · answered by bfengineer07 2 · 0⤊ 0⤋
1. 2 (x^2) / (x^3) = 2 / (x^(3-2)) = 2/x
2. sqrt (x^4) = sqrt ((x^2) * (x^2))= sqrt (x^2) * sqrt (x^2) = x*x
= x^2
3. (2x+4) / 2 = [2 (x +2)] / 2 = x+2.
2007-08-13 18:14:37 · answer #6 · answered by kat79015 2 · 0⤊ 0⤋
1.2x^2/x^3=2/x
2.sqrt(x^4)==/-x^2.
3.(2x+4)/2=x+2.
2007-08-13 18:13:30 · answer #7 · answered by Anonymous · 0⤊ 0⤋