Can Someone help me with these problems?

Question

Can someone help me with these problems because im like lost.

1.) 4(x +5)=6(2x -1)

2.) 2x + 3 = x -7

3.) 2/5 x + 7=13

Answer 1

1. 4(x+5) = 6(2x-1)
4x+20 = 12x -6 subtract 4x both sides
20 = 8x -6 add 6 both sides
26= 8x divide 8 both sides
x= 26/8 = 13/4

2. 2x+3= x-7 subtract x both sides
x+3= -7 subtract 3 both sides
x= -7 -3 = -10

3. (2/5)x +7 =13 subtract 7 both sides
(2/5)x= 6 time 5 both sides
2x= 30 divide 2 both sides
x = 15

Answer 2

1.) 4(x + 5) = 6(2x - 1) Use the distributive property
4x + 20 = 12x - 6 Add like terms to each side
26 = 8x Divide each side by 8
x = 3.25

2.)2x + 3 = x - 7 Add like terms to each side
x = -10

3.)2/5x + 7 = 13 Subtract 7 to the other side
2/5x = 6 Multiply each side with 5/2
x = 15

Answer 3

1.) 4(x +5)=6(2x -1)
4x+20 = 12x -6
4x-12x = -20-6
-8x = -26
x = 26/8 = 13/4 = 3 1/4

2.) 2x + 3 = x -7
2x -x = -7 -3
x = -10

3.) 2/5 x + 7=13
2x +35 = 65
2x = 65-35 = 30
x = 15

Answer 4

1.) 4(x + 5) = 6(2x - 1)
4x + 20 = 12x - 6
20 + 6 = 12x - 4x
26 = 8x
x = 13/4

Answer: x = 3 1/4 or 3.25

2.) 2x + 3 = x - 7
2x - x = - 7 - 3
x = - 10

Answer: x = - 10

3.) 2/5x + 7 = 13
2/5x = 13 - 7
2/5x = 6
x = 6 / (2/5)
x = 30/2

Answer: x = 15

Answer 5

Problem One
1st Distribute-
4x+5=12x-6
2nd- bring the variables to one side-
5=8x-6
3rd bring the constants to one side-
11=8x
4th divide
x=11/8

Problem Two
1st bring the variables to one side
x+3=-7
2nd bring the constants to one side
x=-10

Problem Three
1st bring the constants to one side
2/5x=6
2nd divide (or multiply by the reciprocal- it's the same thing)
x=6*5/2
x=30/2
x=15

Answer 6

1) 4x + 20 = 12x -6
20 + 6 = 12x - 4x
26 = 8x ............... x = 3.25

2) 2x+ 3 = x -7
2x - x = -7 -3 ...............x = -10

3) 2/5x + 7 = 13
2/5x = 13-7
2/5x = 6 ,,,,,,,,,,,,, x = 15



collect like terms ....

Answer 7

Be specific...all three problems require different solutions methods...

Are all 3 lost to you or is it just easier for someone else to do it for you...