how would i solve this algebra problem...?

Question

write an equation for the line that is parallel to -7x -3y = 3 and that passes through the point (9,-7)

Answer 1

If -7x-3y=3, which is the equation in standard form, first move the "x" values to the opposite side of the "=" sign; -3y=7x+3. The equation is now in what is called "slope intercept form," also known as "y=mx+b." You will need to find a new value for "b," so replace the "3" with "b," since the new equaiton will probably not be the same as the old one; -3y=7x+b. Then, using the given coordinate point (9,-7), replace the "x" with "9" and the "y" with the "-7;" -3(-7)=7(9)+b. Multiply the values together; 21=63+b. Then subtract "63" from the right-hand side, and the result is "b;" -42=b. So the final equation, when put back in standard form, is -7x-3y=-42.

Answer 2

A line parallel to -7x-3y=3 is of the form
-7x-3y=K
If it passes through(9,-7
-63+21=K
K=-42
the desired EQ. of the line is
-7x-3y=-42 ANS..

Answer 3

-7x-3y=3
3y= -7x-3
y = -7/3 x -1
slope for this line will be m = -7/3
and the new line will have the same slope because parallel line so m =- 7/3
linear general equation i s y = mx+b m=slope , b= y-intercept
new line y= -(7/3)*x+b
we need to figure out b
plugged the point (9, -7) to the new line and that means x= 9, y= -7
-7=-(7/3)*9 +b
-7= -21+b add both sides by 21
14= b
so equation is y = -(7/3)x+14

Answer 4

because it is parallel through -7x -3y = 3, it will have the same slope, so
-7x -3y is the first part of the equation.
Next you just have to substitute (9,-7)
-7(9) - 3(-7)= -42
-7x -3y= -42 is answer

Answer 5

3y = - 7x - 3
y = (- 7 / 3) x - 1
m = (- 7 / 3)
Parallel line has same slope (gradient)
Equation of parallel line is:-
y + 7 = (-7/3) (x - 9)
y + 7 = (-7/3) x + 21
y = (-7/3) x + 14
OR
3y = - 7 x + 42
7x + 3y = 42

Answer 6

-7x-3y=-63+21=-42

Answer 7

what he said (: