The rate of increase of thickness of ice on a pond is inversely proportional to the thickness of the ice is x centimetres and the temperature of the air above the ice is -a degrees celcius, the rate is (ax/14400) cm/s. Form an appropriate differential equation, and hence show that, if the -10 degrees celcuis, the time taken for the thickness to increase from 5 cm to 6 cm is a little more than 2 hours.
2007-08-13
09:40:42
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5 answers
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asked by
Anonymous
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Science & Mathematics
➔ Mathematics