write as a simplified radical sqaure root of 6 times square root of 8?

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please help

2007-08-13 09:30:42 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

sqrt6*sqrt8
sqrt2*3*sqrt4*2
sqrt2*sqrt3*sqrt4*sqrt2 cuz sqrt4 = 2, and sqrt2*sqrt2 = 2
2*sqrt3*2
4sqrt3

or 4*3^(1/2)

2007-08-13 09:42:20 · answer #1 · answered by Helper 6 · 0⤊ 0⤋

â6 x â8 = â6 x 2â2 = 2â12 = 2 x 2â3 = 4â3

2007-08-13 10:22:52 · answer #2 · answered by Como 7 · 0⤊ 0⤋

12 times the square root of 2

2007-08-13 09:43:51 · answer #3 · answered by Alfred G 1 · 0⤊ 0⤋

sqrt(6) * sqrt(8) = sqrt(48)

sqrt(48) = sqrt(16 * 3)
sqrt(48) = sqrt(16) * sqrt(3)
sqrt(48 ) = 4 * sqrt(3)

so, 4*sqrt(3) is your answer

2007-08-13 09:49:14 · answer #4 · answered by kousuke51 2 · 0⤊ 0⤋