Solve the equation.
(x - 7)/ (6) = (x + 3) / (7)
Problem 2
Solve the problem.
Two angles are supplementary if the sum of their measures is 180. If the measure of one angle is given by (31x/20) and the measure of its supplement is given by ( 7x/10), find the measures of the two angles.
62, 118
80, 100
40, 140
124, 56
2007-08-13 08:28:53 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(x - 7)/ (6) = (x + 3) / 7
crossed multiply
7(x-7) = 6(x+3)
7x -49= 6x+18
subtract both sides by 6x
x-49= 18
add both sides by 49
x= 18+49 = 67
problem 2
supplementary that means the sum of angles is 180
let A, and B are two angles we wanna find
A+B =180 and they have given A= 31x/20 and B=7x/10
31x/20 +7x/10 = 180 LCD=20
31x(1) +7x*2= 180*20
31x+14x= 180*20
45x= 3600
x = 3600/45 = 80
A= 31*80/20 = 124, B= 7*80/10 =56
answer is 124, 56
good luck buddy
2007-08-13 08:43:15 · answer #1 · answered by Helper 6 · 0⤊ 0⤋
Solve as a proportional problem
Cross Multiply
(x - 7) / 6 = (x + 3) / 7
The Means = 6(x + 3)
The extremes = 7(x - 7)
6(x + 3) = 7(x - 7)
The distributive property
6x + 18 = 7x - 49
Transpose 6x
6x + 18 - 6x = 7x - 49 - 6x
18 = x - 49
Transpose 49
18 + 49 x - 49 + 49
67 = x
- - - - - - - -
Check
(67 - 7) / 6 = *67 + 3) / 7
60 / 6 = 70 / 7
10 = 10
- - - - - - - -s-
2007-08-13 08:54:39 · answer #2 · answered by SAMUEL D 7 · 0⤊ 0⤋
for the first one you need to cross multiply and solve for x.
(x-7) (7) = (x+3) (6)
then distribute and solve for x.
second one. they say the angles have to sum to 180.
so (31x/20) + (7x/10) = 180
get a common denominator (or multiply through by 20 to get rid of the fractions), then solve for x.
2007-08-13 08:41:39 · answer #3 · answered by quote23lover 1 · 0⤊ 0⤋
1) cross multiply
7(x-7) = 6(x+3)
solve
x = 67
plug back in and check
2)set up equation
31x/20 + 7x/10 = 180
solve
31x/20 + 14x/20 = 180
45x/20=180
x=80
plug x into original angles
angle1 = 124
angle2 = 56
2007-08-13 08:43:15 · answer #4 · answered by Pawn 2 · 0⤊ 0⤋