12. Write the first six terms of each of the sequences whose nth term is
(a) ( -3) n
(b) 3 – 4n
2007-08-13 08:23:39 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
To get the first 6 terms of any sequence defined with an equation in "n", simply substitute the values 1 through 6 in for n and simplify. I'll do (a):
1st term: (-3)·1 = -3
2nd term: (-3)·2 = -6
3rd term: (-3)·3 = -9
4th term: (-3)·4 = -12
5th term: (-3)·5 = -15
6th term: (-3)·6 = -18
2007-08-13 08:30:49 · answer #1 · answered by Tony The Dad 3 · 1⤊ 0⤋
Just replace n with the numbers 1, 2, 3, 4, 5, 6 in turn, then perform the operation.
For example, is the first one is "minus three" multiplied by n, then the first three terms are:
(-3)*1, (-3)*2, (-3)*3 =
-3, -6, -9
2007-08-13 15:29:21 · answer #2 · answered by Raymond 7 · 0⤊ 0⤋
a) 0, -3, -6, -9, -12, -15 For n = 0... n = 5
b) 3, -1, -5, -9, -13, -17 For n = 0... n = 5
2007-08-13 15:28:45 · answer #3 · answered by Edgar Greenberg 5 · 0⤊ 0⤋
you have to define what the range for n is...
assumin n is 0 to i
a) 0, -3, -6, -9, -12, -15
b) 3, -1, -5, -9, -13, -17
2007-08-13 15:28:36 · answer #4 · answered by Pawn 2 · 0⤊ 0⤋
first 6 terms means n is successively 1 through 6
a) -3,-6,-9,-12,-15,-18
b) -1,-5,-9,-13,-17,-21
2007-08-13 15:30:14 · answer #5 · answered by chasrmck 6 · 0⤊ 0⤋
It seems to me there is insufficient information to answer the questions with a single answer. Rather, there are an infinite number of solutions for each question.
2007-08-13 15:38:17 · answer #6 · answered by statrnan 1 · 0⤊ 0⤋