chem question?

Question

consider the formation of a solution of aqueous potassium chloride. Write the thermo chemical equations for
a. the conversion of solid KCl into its gaseous ions
b. the subsequent formation of the solution by hydration of the ions.
The lattice energy of KCl is -690 kJ mol^-1, and the hydration energy of the ions is -686kK mol^-1. Calculate the heat of solution of KCl in kJmol^-1

Answer 1

KCl(s) -----> K+(g) + Cl-(g)

K+(g) + Cl-(g) + aq ------> K+(aq) + Cl-(aq)

690 - 686 = +4 kJ/mol