English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

The answer should be x=4... It's been a while since I've worked with logarithms.. So a quick refreshment would be fantastic.

2007-08-13 06:43:22 · 5 answers · asked by G S 1 in Science & Mathematics Mathematics

5 answers

If ln A = ln B then A = B
2x - 1 = x + 3
x = 4

2007-08-13 07:40:14 · answer #1 · answered by Como 7 · 0 0

Since the ln has been taken on both sides:
ln (2x-1)=ln (x+3) === (2x -1) = (x + 3)
Solving for x
2x - x = 1 + 3
x = 4

2007-08-13 13:47:13 · answer #2 · answered by dr_no4458 4 · 0 0

Hey there!

Here's the answer.

ln(2x-1)=ln(x+3) --> Write the problem.
2x-1=x+3 --> Use one-to-one property of logarithms i.e. if ln(a)=ln(b), then a=b.
x-1=3 --> Subtract x on both sides of the equation.
x=4 Add 1 on both sides of the equation.

So the answer is x=4.

Hope it helps!

2007-08-13 13:58:22 · answer #3 · answered by ? 6 · 0 0

take out ln, we can get 2x-1 = x +3 so x =4

2007-08-13 13:47:28 · answer #4 · answered by Master 2 · 0 0

ln(2x - 1) = ln (x + 3)
-> ln(2x - 1) - ln (x + 3) = 0
-> ln[(2x - 1)/(x + 3)] = 0 = ln 1
-> (2x - 1)/(x + 3) = 1
-> 2x - 1 = x + 3
-> x = 4

2007-08-13 13:49:23 · answer #5 · answered by dy/dx 3 · 0 0

fedest.com, questions and answers