How many moles of NaOH are required to prepare 0.250L of 6.68M NaOH?
2007-08-13 06:14:15 · 4 answers · asked by philip c 1 in Science & Mathematics ➔ Chemistry
To do this, we must first write this as an equation:
6.68M= (x moles)/(.250L)
After this, we realize that to find the number of moles, you simply multiply 6.68 by .250 to get the number of moles, which is 1.67moles.
2007-08-13 06:47:14 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I'm guessing the question is supposed to be:
How many moles of NaOH (s) are required to prepare 0.250L of 6.68M NaOH (aq)?
If so here is the solution:
n = cV
n being moles (mol)
c being concentration (M - molarity or mol/L - moles per litre)
V being volume (L - litres)
n = 6.68 M * 0.250 L
n = 26.72 mol
n = 26.7 mol (scientific notation)
2007-08-13 13:22:46 · answer #2 · answered by Anonymous · 0⤊ 1⤋
Actually, this may seem like chemistry, but it's really just math:
A 1 Molar solution is made with 1 mole of substance per 1 Liter of solvent.
A 6.68 Molar Sodium Hydroxide solution requires 6.68 moles of NaOH per Liter, so how much do you need in 1/4 Liter? (spoiler alert! you just divide by four...)
2007-08-13 13:25:18 · answer #3 · answered by John R 7 · 0⤊ 1⤋
I'd rather not help since I'll get it wrong...I got a D in chemistry. I hate dimensional analysis with moles. All I remember is that 1 mole = 1 mole = 6.022 x 10 (superscript)23.
2007-08-13 13:23:03 · answer #4 · answered by Anonymous · 0⤊ 1⤋