t hrs after the southbound car left: ©
50t + 50 + 40t = 320 ......... this is their combined distance
90t = 270
t = 3 hrs.
thus at 6 pm.
2007-08-13 05:12:52
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answer #1
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answered by Alam Ko Iyan 7
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Let x = no. hours for the cars to be 320 mi apart.
(50 + 50x) + 40x = 320
50 + 50x + 40x = 320
90x = 320 - 50
90x = 270
x = 270 / 90
x = 3
3:00 PM + 3
Answer: 6:00 P.M.
Proof:
50 + (3 * 50) + (3 * 40) = 320
50 + 150 + 120 = 320
320 = 320
2007-08-17 03:37:03
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answer #2
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answered by Jun Agruda 7
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50 + 50t + 40t = 320, where t = time after 3 pm. Then 90t = 270, t = 3, so they will be 320 mi. apart at 6 pm.
2007-08-13 12:16:52
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answer #3
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answered by John V 6
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at 1 hour those cars will be at 90mi aprt. then 320mi/90mi = 3.55..... so 3.56 times 60 is equal to 213.6 which is also equal to 213.6 minutes
so its 3 hours and 30 minutes (estimately)
so 1400h + 0330h = 1730h which is 5 : 30 pm
so at 5:30 pm the cars will be apart 320mi
2007-08-13 12:16:43
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answer #4
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answered by oOo_tophothari_oOo 3
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The second car is driving WAY too slow. I swear I was behind that guy on the freeway this morning. I honked at him.
2007-08-13 12:14:38
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answer #5
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answered by Nunya 4
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Maybe 530pm
What if they cross a time zone.
2007-08-13 12:13:57
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answer #6
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answered by adam h 3
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Who cares? Why do they keep making people do this?
2007-08-13 12:14:25
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answer #7
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answered by Elaine P...is for Poetry 7
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the second tuesday of next week!
2007-08-13 12:15:01
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answer #8
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answered by Anonymous
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6 pm...now do your own homewrk
2007-08-13 12:14:45
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answer #9
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answered by leprechaun3833 5
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idonnaknow
2007-08-13 12:12:55
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answer #10
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answered by Anonymous
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