xy + 4y + xz + 4z
Any help would be appreciated.
2007-08-13 04:37:04 · 8 answers · asked by Heyr89 1 in Science & Mathematics ➔ Mathematics
= x (y + z) + 4(y + z)
= (y + z) (x + 4)
2007-08-13 05:05:33 · answer #1 · answered by Como 7 · 0⤊ 0⤋
Since there are four terms, try to factor by grouping terms with a common factor.
xy + 4y + xz + 4z =
(xy + 4y) + (xz + 4z) =
(x + 4)y + (x + 4)z =
(x + 4)(y + z). [Distributive law]
Similarly,
(xy + xz) + (4y + 4z) =
x(y + z) + 4(y + z) =
(x + 4)(y + z).
2007-08-13 11:59:59 · answer #2 · answered by S. B. 6 · 0⤊ 0⤋
xy+4y+xz+4z
=y(x+4)+z(x+4)
=(x+4)(y+z). ANS.
2007-08-13 11:46:31 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Factor out y from the first two terms and then z from the last two terms:
y(x+4) + z(x+4)
Now, factor out (x+4):
(x+4)(y+z)
You can use FOIL to check your work:
xy + 4y + xz + 4z
2007-08-13 11:45:50 · answer #4 · answered by Larry C 3 · 0⤊ 0⤋
xy + 4y + xz + 4z = y(x+4) +z(x+4) = (x+4)(y+z)
2007-08-13 11:54:44 · answer #5 · answered by the DoEr 3 · 0⤊ 0⤋
Grouping factors
xy + 4y + xz + 4z
= y( x+4 ) + z( x+4 )
= (y+z)(x+4)
QED
2007-08-13 11:53:17 · answer #6 · answered by harry m 6 · 0⤊ 0⤋
x(y+z) + 4(y+z) = (y+z)(x+4)
2007-08-13 11:43:17 · answer #7 · answered by jedd c 3 · 0⤊ 1⤋
(x+4)(y+z)
2007-08-13 11:47:58 · answer #8 · answered by Blair V 3 · 0⤊ 0⤋