A large truck and a car, both moving with a velocity of magnitude 'v', have a head-on collision and both of them come to a halt after that. If the collision lasts for one second:
1) Which vehicle experiences the greater force of impact?
2) Which vehicle experiences the greater change in momentum?
3) Which vehicle experiences the greater acceleration?
4) Why is the car likely to suffer more damage than the truck?
If you get it right, I'll give you 10 points! (it's so easy!)
2007-08-13
01:30:10
·
5 answers
·
asked by
that's me™
1
in
Science & Mathematics
➔ Physics
TRUCK►◄car
◙—►◄—◘
◙ = force of tuck on car
◘ = force of car on truck
SAME AMOUNT OF FORCE
DIFFERENT RESULTS
2007-08-13
01:34:33 ·
update #1
1) The large truck, as a direct result of answer 2). (Force is equal to change in momentum divided by change in time.)
2) The large truck, because it had more momentum to start with due to its larger mass, and both the truck and car ended up with zero momentum due to zero velocity.
3) They experience equal acceleration, because they experienced equal changes in velocity over the same time period.
4) It's a consequence of equal and opposite reactions. The huge force that acted on the truck was exerted by the fender of the car, crushing it. The smaller force on the car was exerted by the cab of the truck, and wasn't as damaging.
2007-08-13 01:42:46
·
answer #1
·
answered by DavidK93 7
·
2⤊
1⤋
They are both traveling the same velocity, which means if they both stop in 1 second, they both have the same acceleration.
1. F = ma. since they have the same acceleration, the car with the most force is that which has the greatest m, so the truck would have the greatest force F, assuming the truck has a greater mass.
2. momentum = mv. After the collision, both cars have a momentum of 0 (because v=0). So the greatest change in momentum is the vehicle with the greatest initial momentum, and again, because they have the same velocity, this is dependent on the mass, m. So the truck again, experiences the greatest change in momentum.
3. Since both of the vehicles stop in 1 second, and they both started with the same velocity, they will have the same acceleration. Acceleration doesn't necessarily depend on mass.
4. Finally, the car is likely to suffer more damage because it is lighter. Since it had less kinetic energy, (1/2mv^2, where m is less), but they both have the same final energy (0, because they are stopped), this means the car had to absorb more of this energy in the collision. Since in a collision the only place for the energy to go is into crushing the car, the car will experience more damage than the truck.
2007-08-13 01:40:24
·
answer #2
·
answered by Jon G 4
·
2⤊
0⤋
first after collision they would not stop this is against the conservation of momentum. truck has a larger momentum MV compared to the car mV; M>m; since there is no external force after collision, assuming it is completely plastic i.e. they stick together after collision, they would move with the speed of (m+M)V2=MV-mV
V2= V(M-m)/(M+m) in the direction of speed of the truck.
so the truck will have a change in speed equal to V-V2 and the car would have a change in speed equal to -V-V2 which is larger in magnitude than truck's speed change.
1) based on newtons third law both will experience the same magnitude of force in different directions (no doubt).
2) since they experience the same force in the same duration the change in momentum is equal d(mv)=Fdt.
3) since the change in velocity of the car is larger in the same period of time, the car experience larger acceleration.
4) this is a stupid question there is no way to prove it would damage more, imagine you have a very solid car hitting a soft truck, truck would have more plastic deformation (irreversible deformation), it depends on the rigidity of the car and the truck. just ro make it clear compare it with the collision of a human who jump on the rigid earth one time and a soft balloon the next time. but since human inside the car tend to keep their momentum (1st Newton) they would suffer a larger force due to larger acceleration, which may cause damage to humans inside the car; this is because of weakness of the human body structure.
by the way keep your points ! :)
2007-08-13 02:05:45
·
answer #3
·
answered by masoud 2
·
1⤊
0⤋
if its so easy.why not solve it for urself!!!
Anyways here goes the answer.......
1.car
(truck has greater mass n therefore for same cvelocity,truck will have greater momentum n hence impart greater force on car after collison)
2.truck
Mv is momentum change for truck
mv is change for vehicle(both come to rest ,change =final-initial)
And M>>v
3
More momentum of truck,more force imparted to vehicle by truck(Newtons law),more the collison force on vehicle,more is its accl..............
4. due to higher force acting on it..........
law of conv of momoentum can be applied n it becomes clear that impact on vehicle is more severe......
2007-08-13 01:41:58
·
answer #4
·
answered by amudwar 3
·
0⤊
2⤋
this question is from ncert 9th text book ,this question doesnot make sense therefore this year book it is omitted,answer given by masoud is correct after some changes in question.
2016-09-18 01:22:58
·
answer #5
·
answered by Rekha 1
·
0⤊
0⤋