help me solve this problem pls!!!!!!!!!!!!?

Question

After 5 hours of house painting,Peter asked the assistance of James.Together they finished the job in 4 more hours.Had James painted in an hour after Peter started working,the job would have been finished in 7 hours.How long would it take Peter to paint the house alone?

Answer 1

9/P + 4/J = 1
7/P + 6/J = 1
4/J = 1 - 9/P
6/J = 6(1 - 9/P)/4
7/P + (6 - 54/P)/4 = 1
28/P + 6 - 54/P = 4
28 + 6P - 54 = 4P
2P = 26
P = 13 hrs

Answer 2

These problems aren't that hard when you break them down.

Let X be the rate that Peter works at & let Y be the rate that James works at.

Peter works for 9 hours and James works for 4 -- so:

9X+4Y = 1

The second part tells us that if Peter worked for 7 hours and James had worked for 6 -- then the job would have been completed -- this gives us:

7X+6Y = 1

You now have two equations in two unknowns -- so there is a unique solution.

You do the rest.

Answer 3

11 hours

Answer 4

F*CK MATH!