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f(x)=(x-4)(x+2)(x-1)

also is (x-3) a factor of
p(x)=x^4-5x^2-27x+15

2007-08-12 13:54:44 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

For the first question, set each factor to zero and solve.
The zeros are 4, -2 and 1.
For the second question:
The answer is "no".
x-3 is a factor of p(x) if and only if p(3) = 0.
But p(3) = 81-45-81 + 15 = -30.

2007-08-12 14:19:39 · answer #1 · answered by steiner1745 7 · 1 0

4,1,-2

2007-08-12 21:03:08 · answer #2 · answered by bradlelf 2 · 0 0

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