a. 2-butanol
b. 2-pentanol
c. 2-methylpropanol
d. 2,2-dimethylbutane
e. pentanal
2007-08-12 10:30:11 · 4 answers · asked by sikhism4life88 1 in Science & Mathematics ➔ Chemistry
I think the answer you are looking for is 2-pentanol. 2-pentanol is a constitutional isomer (ie structural isomer) not a geometric isomer. A geometrical isomer is an obsolete term for cis-trans isomerism. It is sometimes used interchangeably with optical isomerism but this is not a correct use of the term. Hope this helps and good luck.
2007-08-12 10:37:22 · answer #1 · answered by Anonymous · 1⤊ 0⤋
None of them show geometrical isomerism. To show geometrical isomerism the compound must have a double bond, as in alkenes.
However, geometrical isomerism is a form of stereoisomerism (compounds which have the same structural and molecular formula but differ in the spatial arrangement of one or more atoms). In this case pentan-2-ol is a stereoisomer as the no.2 carbon is assymetric i.e. has 4 differnt groups attached to it (H, OH, CH3, and C3H7) making it an optical isomer but not geometric.
2007-08-16 09:16:43 · answer #2 · answered by bragglen 1 · 1⤊ 0⤋
None of the above. There are no geometrical isomers of 1-pentanol
2007-08-12 10:36:37 · answer #3 · answered by steve_geo1 7 · 2⤊ 0⤋
there is no geometrical isomer, but b) is a structural isomer
2007-08-13 23:25:17 · answer #4 · answered by oompa loompa 2 · 1⤊ 0⤋