How to calculate the force of a falling object?

Question

Please derive or show the formula used to calculate this. Neglect air risistance

mass x acceleration constant gives us the weight of the object, also a force exerted onto the ground.

However, F= M x A cannot be the same force as a so called impact force.

For example, if i were to place 100lbs on my desk right here, the desk would hold it and nothing would break, but if i drop it from 15 feet above, the desk collapses, or puts a nice big hole in it.

The resting force (F=M x A) is not equal to a falling force.

This is just my thought, could be wrong, but it makes more sense to me

Answer 1

Isn't it pretty much just F = ma?

Answer 2

I think what you are looking for is the force needed to stop a falling body. This force needs to take into account how long the object is in contact with the surface it's falling on. For example, if the thing crumples, it will exert a smaller force than something very hard bouncing off. The average force of an object ravelling at v and coming to a stop will be

(mv)/t

Answer 3

what i think you are referring to is the net force (sum of all of the forces). when the weight sits on the table, there are two forces acting on it, force due to gravity and the force from the table (normal force). these are exactly equal in magnitude and opposite in direction, so the net force is 0. when the weight is falling, there is a net force which would equal the weight (force due to gravity) minus the force from air resistance (small initially).

Answer 4

f=ma

acceleration=9.81 m/s/s (we know this from experiments)

Find the mass and the rest is easy.

I wish I could give you ore but that is all there is to it.

Answer 5

F=mg, where m is mass and g is gravity (9.81 m/s^2)