(-6,2), (2,0), (-10,-3), (-18,5) are solutions for the equation x+4y=2?
I have tried to solve this problem and I cannot figure it out. I have never had an Algegbra class before now and I am really lost. If you could show the work so I can take notes, would be greatly appreciated. Thank you.
2007-08-12 07:48:44 · 4 answers · asked by ? 1 in Science & Mathematics ➔ Mathematics
1, 2, and 4.
Replace the pairs of numbers in and check.
Note that (-10, -3) would work too, if "-3" were positive "3".
2007-08-12 07:52:25 · answer #1 · answered by Anonymous · 0⤊ 0⤋
you have to plug in the coordinate to check
x + 4y = 2
-6 + 4(2) = 2
-6 + 8 = 2
2 = 2 true
2 + 4(0) = 2
2 = 2 true
-10 + 4(-3) = 2
-10 - 12 = 2
-22 = 2 false
-18 + 4(5) = 2
-18 + 20 = 2
2 = 2 true
so (-2,2), (2,0) and (-18,5) are the solutions
2007-08-12 14:55:04 · answer #2 · answered by 7 · 0⤊ 0⤋
Plug them into the equation:
(-6, 2): -6 + 4*2 = -6+8 = 2
(2, 0): 2+4*0 = 2
(-10, -3): -10 + 4*(-3) = -10 - 12 = -23 =/= 2
(-18,5): -18 + 4*5 = -18 + 20 = 2
2007-08-12 14:55:44 · answer #3 · answered by Amit Y 5 · 0⤊ 0⤋
it should be (2,0)is the soulution cuz u c 4times0is 0 right and then u add 2 then the answer is 2 right
2007-08-12 14:59:09 · answer #4 · answered by Je m'appelle Sophie 3 · 0⤊ 0⤋