write the expression in the form a +bi, where a and b are real numbers.
2007-08-12 06:56:28 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
= - 12 i ² + 3i
= 12 + 3 i
2007-08-12 07:11:55 · answer #1 · answered by Como 7 · 3⤊ 0⤋
12+3i
2007-08-12 14:12:44 · answer #2 · answered by PRADEEP K 1 · 0⤊ 2⤋
-3i(4i -1)
= -12 i^2 + 3i
= -12(-1) + 3i
= + 12 + 3i
2007-08-12 13:59:39 · answer #3 · answered by harry m 6 · 0⤊ 0⤋
-3i(4i-1)
=-3i*4i+3i
=-12i^2+31 since i^2=-1 by definition
=-12*(-1)+3i
=12+3i
2007-08-12 14:02:49 · answer #4 · answered by Joe stevens 2 · 0⤊ 0⤋
i^2 = -1
so: -12(i^2) + 3i = 12+3i
2007-08-12 14:00:11 · answer #5 · answered by Bob R. 6 · 0⤊ 0⤋
-(12i^2-3i)
12+3i
2007-08-12 14:00:35 · answer #6 · answered by phanis9881 1 · 0⤊ 0⤋
-3i(4i - 1) => -12i^2 + 3i
=>3i - 12i^2 =>3i(1 - 4i)
is it right??????????:-(
2007-08-12 14:03:34 · answer #7 · answered by Rokkky 2 · 0⤊ 1⤋
12+3i
a=12
b=3
2007-08-12 13:59:28 · answer #8 · answered by GalNextDoor 4 · 0⤊ 0⤋