Find the integers
2007-08-12 06:25:07 · 7 answers · asked by noidea 1 in Science & Mathematics ➔ Mathematics
Let consecutive odd integers be 2x + 1 and 2x + 3
2(2x + 3) = 3(2x + 1) - 13
4x + 6 = 6x + 3 - 13
4x + 6 = 6x - 10
2x = 16
x = 8
Integers are 17 and 19
2007-08-16 02:14:36 · answer #1 · answered by Como 7 · 0⤊ 0⤋
enable x be the smaller integer. they are consecutive peculiar, so as that they have a distinction of two. subsequently, the better integer is x + 2. sparkling up for x. 2 * better = 3 * Lesser - 13 2(x + 2) = 3x - 13 2x + 4 = 3x - 13 -x + 4 = -13 -x = -17 x = 17 The integers are 17 and 19.
2016-11-12 03:05:48 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Let the lesser odd integer be x
therefore the next greater odd integer is x + 2
Twice the greater is 2(x + 2)
Thrice the lesser is 3x
According to the question,
Twice the greater = Thrice the lesser - 13
therefore,
=>2(x + 2 ) = 3x - 13
=>2x + 4 = 3x - 13
=>4 + 13 = 3x - 2x
=>17 = x
thus x = 17
hence,
the integers are x and x + 2 which is,
17 and 17 + 2=19
=>>>17 and 19
2007-08-12 06:35:26 · answer #3 · answered by Rokkky 2 · 0⤊ 0⤋
Smaller integer: x
Larger integer: x+2
2(x+2) + 13 = 3x
2x+4+13 = 3x
x = 17, x+2 = 19
To check: we have: 51-38 = 13, so this is correct.
2007-08-12 06:30:09 · answer #4 · answered by Bob R. 6 · 1⤊ 0⤋
17*3=51 19*2=38
51
-38
__
13
The integers are 17 and 19
2007-08-12 07:30:22 · answer #5 · answered by Haley 1 · 0⤊ 0⤋
the integers are 17 and 19
19 x 2 = 38
38 + 13 = 51
51 / 3 = 17
2007-08-12 06:37:23 · answer #6 · answered by Not bad for a cabbage! 2 · 0⤊ 0⤋
let the two consecutive odd integers be (2n-1) and (2n+1)
2(2n+1)=3(2n-1)-13
4n+2=6n-16
2n=18
n=9
the reqd numbers are 17,19.ANS.
2007-08-12 06:34:41 · answer #7 · answered by Anonymous · 0⤊ 0⤋