1. Find the measures of the other three angles of a parallelogram of one angle measures:
b. 68
thank you! can you show me the work plz
2007-08-12 06:24:28 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Have two angles of 68 °
Sum of these = 136 °
Angles of parallelogram add to 360 °
Other two angles add to 224 °
Angles are 68 ° , 68 ° , 112 ° , 112 °
2007-08-12 07:20:35 · answer #1 · answered by Como 7 · 3⤊ 0⤋
It's easy.
If you have a parallelogram ABCD and you have the angle of A = 68degree, then you can remember two things :
1. the opposite angle of A in parallelogram having same angle as A
Hence, the angle of C are 68degree
2. The total of degree in a 4-section lines (ex. parallelogram, box, squares etc) are 360degrees.
You have two angles : A=C = 68degrees
The total of B+D are
B+D=360 - (A+C)
= 360 - (68 +68)
= 360 - (136)
= 224
Hence, B=D=224/2=112degrees
Now you have the answer
A=68degrees
B=112degrees
C=68degrees
D=112degrees
Cheers
2007-08-12 13:36:30 · answer #2 · answered by Mohamad Radhian M 3 · 0⤊ 0⤋
opposite angles of a parallelogram are congruent.
therefore, m/_A=m/_C AND m/_B=m/_D
sum of the measures of the angles of a parallelogram is 360 degrees
therefore,
A+B+C+D=360
A+68+C+68=360
A+C=360-136
2A=224 (SINCE A=C, A+C IS SAME AS A+A=2A)
A=112 DEGREES
2007-08-12 13:51:33 · answer #3 · answered by Sean 3 · 0⤊ 0⤋
subtract 68 from 90 to get the and add the differance to 90 to get the measure of the larger angle.should be the same for the other side
2007-08-12 13:33:35 · answer #4 · answered by Roz 3 · 0⤊ 0⤋