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2007-08-12 05:31:56 · 26 answers · asked by Anonymous in Science & Mathematics Mathematics

26 answers

friend .
it has been answered correctly by many already.
I think if you just look into your maths book you will see it.i Wonder why you don't even try that?
If there is a difficult question ,or if there is any difficulty in application of it , you are welcome.I suggest that you must make minimum effort and shall not expect to be helped by others , while you sit idle doing nothing.That is not what a student of maths or any subject do.
any way the answer is again given:
sin(a+b) = sin(a)cos(b) + cos(a)sin(b)
But ii REQUEST YOU TO BE STUDIOUS TO BE A STUDENT .PLEASE DO IT.

2007-08-12 05:47:38 · answer #1 · answered by Radhakrishna( prrkrishna) 7 · 0 4

a = 3
b = 4

sin (7) = 0.12

or it could be one of those trig formulas.

= sin Acos B + Cos A sin B
= SIN 3 cos 4 + cos 3 sin 4
= 0.119
= 0.12

see why dont they just do the first bit. the common sense approach

2007-08-12 05:36:15 · answer #2 · answered by Anonymous · 1 1

sin (A + B) = sin A cos B + cos A sin B

Check out the web page below and bookmark it if you are taking trig.

2007-08-12 05:49:43 · answer #3 · answered by 037 G 6 · 0 0

"TJ" and the others have given you a very good correct answers. But ("TJ")'s first method works only if both "a" and "b" are known, and sin of these quantities are known or easily found in table or on calculator or on a computer.

Formula is more universal and comes handy in many other applications.

PS
When you have time look up the dervation of this formula.

Sin(A+B) = SinACosB + CosASinB

You may find it very interesting.
********************************************

More interesting will be to see if you can take,

SinACosB + CosASinB and come up with the answer.

Sin(A+B)

2007-08-12 05:54:46 · answer #4 · answered by minootoo 7 · 0 1

sin(A+B)=sin A cos B + cos A sin B

2007-08-12 05:39:29 · answer #5 · answered by Anonymous · 0 0

sin a cos b +cos a sin b

2007-08-16 04:01:37 · answer #6 · answered by Anonymous · 0 0

Hey there!

If you're expressing sin(a+b), in terms of sine and cosine, the answer would be sin(a)cos(b)+sin(b)cos(a).

This is called the sum identity for sine.

Let's take an example.

sin(pi) -->
sin(pi/2+pi/2) -->
sin(pi/2)cos(pi/2)+sin(pi/2)cos(pi/2) -->
1(0)+1(0) -->
0+0 -->
0

So the answer is 0.

Hope it helps!

2007-08-12 05:49:58 · answer #7 · answered by ? 6 · 0 0

sin(a+b)= sin a cos b + cos a sin b.

2007-08-12 05:59:07 · answer #8 · answered by Anonymous · 0 0

sin(a+b) = sin(a)cos(b) + sin(b)cos(a)

for example,

a= 30
b=60

sin(30+90) = sin(30)cos(60) + sin(60)cos(30)
= 0.5 * 0.5 + sqrt(3)/2 + sqrt(3)/2
= 1/4 + 3/4
= 1

Hope this helps!

2007-08-12 05:38:34 · answer #9 · answered by alrivera_1 4 · 0 1

sin(a+b)=sin a cos b+cos a sin b
sin(a-b)=sin a cos b-cos a sin b

2007-08-12 05:39:15 · answer #10 · answered by nat_90311 2 · 0 0

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