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Ok I need help solving the binomial multiplication problem of (x+6)^2. If the answer is x^2+36 please let me know.

2007-08-12 04:55:29 · 12 answers · asked by hoopbredkb24 1 in Science & Mathematics Mathematics

12 answers

uhm... then either the book [from which u got the answer from] or your teacher [who gave you the answer] is wrong.

if you multiply out (x+6)^2 then you are doing this:

(x+6)(x+6)...which is x^2 + 12x + 36...

[this is done by taking the x * x, x * 6, 6 * x, 6 * 6...and grouping like terms.]

2007-08-12 05:04:22 · answer #1 · answered by xscreamstarx 2 · 0 0

For binomial multiplication, its easiest just to rewrite the problem straight-up.

(x + 6)^2 = (x + 6) * (x + 6)

1. So you take the first term (x) on the left side, and multiply it by x on the right side. So you write down

( x + 6 )^2 = x^2 ...

2. Multiply the left side x by the six on the right side, and write that down too.

( x + 6 )^2 = x^2 + 6x ...

3. Take the 6 on the left side and multiply it by the x on the right side.

( x + 6 )^2 = x^2 + 6x + 6x ...

4. Finally, take the 6 on the left side, and multiply it by the 6 on the right side.

( x + 6 )^2 = x^2 + 6x + 6x + 36
( x + 6 )^2 = x^2 + 12x + 36

There's your answer! This is commonly called FOILing, but its easiest just to think that all terms (things separated by a + or - ) must be multiplied together at some point.

2007-08-12 05:10:14 · answer #2 · answered by Skippy D 2 · 0 0

(x + 6)^2 = x^2 + 12x + 36

Let us see how.

x + 6 multiplied by x + 6 gives

x.x + x.6 + 6.x + 36 (where the . represents the multiplication)

= x^2 + 12x + 36 (since x.6 and 6.x are same)

I hope it is clear.

2007-08-12 05:10:43 · answer #3 · answered by Swamy 7 · 0 0

(x+6)^2=(x+6)(x+6) Use FOIL Method.
(x+6)^2=x^2+6x+6x+36
(x+6)^2=x^2+12x+36

You know there are 'formulas' about these equations. They only apple to equations with 2 variables --> an x and y. (example is x and 6 in your equation, the signs may vary) We had them last year. I'm in third year highschool(junior) and I'm fourteen.

BTW, if you don't know Foil Method:
(x+6)(x+6)
F-First variables or terms
O-Outer
I-Inner
L-Last
Multiply the first term of the first factor(x+6) to the first term of the second factor (x+6) The first terms f both factors is x. therefore you square x. = x^2

Outer- Multiply the outer terms/variables. (the left-most and right-most variables) therefore in the equation (x+6)(x+6), the outer terms are x(left) and 6(right). = 6x

Inner- Multiply the terms in the middle. (x+6)(x+6) the middle terms are 6(from the left side)and x(rightside). therefore another 6x.

Last- Multiple the last terms of both factors. (x+6)(x+6) 6 is the last term of both factors therefore you square 6. you now have 36. then add all the similar terms. and put them in the order of decreasing degree.

It'll be easier if you draw lines from a variable to another variable.

2007-08-12 05:13:39 · answer #4 · answered by thedarkthingie 1 · 0 0

Your ans is wrong.
It wud b like this,
(x + 6)^2 = (x)^2 + (6)^2 + 2 * x * 6
=x^2 + 36 + 12x = x(x+12) + 36
or x^2 + 12(3 + x)
You all don't know maths......
it is an identity that,
(a+b)^2 = a^2 + 2ab + b^2
in your problem.....a is x and b is 6.

2007-08-12 05:27:57 · answer #5 · answered by Rokkky 2 · 0 0

that is not the answer. When you square a binomial, you need to write it out twice, and then multiply it together (FOIL method).

(x+6) (x+6) =
x^2 + 6x + 6x + 36 =
x^2 + 12x + 36

2007-08-12 05:04:33 · answer #6 · answered by Brenda L 1 · 0 0

It's x + 6 multiplied by itself.

(x + 6) * x = x^2 + 6x

(x + 6) * 6 = 6x + 36

Add the two products to arrive at the final answer.
x^2 + 6x + 6x + 36
x^2 + 12x + 36

Answer: x^2 + 12 + 36

2007-08-16 02:01:30 · answer #7 · answered by Jun Agruda 7 · 3 0

your answer is incorrect. You have to use the distrubitive property to get the answer. Set it up as (x+6)(x+6). The answer would be x^2+6x+6x+36, or x^2+12x+36.

2007-08-12 05:04:57 · answer #8 · answered by Ed S 4 · 0 0

no

its x^2 + 12x + 36

2007-08-12 05:05:45 · answer #9 · answered by Anonymous · 0 0

no, when you multiply (x+6) and (x+6), you also have to multiply the first 6 by the second x, as well as the first x by the second 6. I know that's a little confusing. try it again.

2007-08-12 05:06:20 · answer #10 · answered by pinkass 2 · 0 0

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