wht is the number of ions of barium ions in 0.05g of barium chloride(BaCl2)?

Question

PLZ ANSWER me soon with steps

Answer 1

First, determine the number of moles of BaCl2 by dividing the mass by the molar mass:

.05 g / 207.993g = .00024 moles

Since the ratio of Ba compared to the overall compound is 1:1, you also have .00024 moles of Ba2+ ions. Now, find the number of ions using Avogadros number:

.00024 moles * 6.02 * 10^23 = 1.4 x 10^20 ions

Answer 2

The mass of BaCl2 is 137.3+2*35.45 = 137.3+70.9 =208.3g

so 0.05g is in mole 0.05/208.3=2.4*10^-4mole

as a molecule of BaCl2 gives 1 ion of Ba++
(BaCl2--> Ba+++2cl-)

so you have 2.4*10^-4 ion gram of Ba++

and in ions 210^-4*6.02210^22 =1.45 10^19 ions