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Hi, i'm having real trouble understanding the schrodinger equations (the time dependent and time-independent), can anyone explain simply what the difference is between the two, and what they are used for ?
Anyone that explains this as simply as possible, and without the use of too much maths will get 10 points.
Thanks, David.

2007-08-12 02:37:13 · 5 answers · asked by David M 1 in Science & Mathematics Physics

5 answers

The above answer is great, but to get at the heart of what they are used for: they are used to model the behavior of quantum mechanical (usually small) systems. The t-d eq. gives the system's evolution in space and time, whereas states of constant energy, which vary trivially with time, the spatial part is of greater interest--say, to find the electron density of a molecule.

2007-08-12 12:02:00 · answer #1 · answered by supastremph 6 · 0 0

Of the two, the time-dependent SE is the more fundamental. The time-independent SE is an application of it, when you want to find specific energy values.

The RHS of each of them is the same: It's the Hamiltonian operator (the energy operator) that acts on the wavefunction. In the case of a point particle in a potential well, the RHS is like:
RHS = (-(hbar)^2/(2m) Laplacian + V(x)) f(x,t)

(Laplacian = d2/dx2 in 1-dimension)

where f(x,t) is the wavefunction.

The LHS of the time-dependent equation is:
LHS = i*hbar*df/dt , so the full time-dependent SE is:
i*hbar*df/dt = (-(hbar)^2/(2m) Laplacian + V(x)) f(x,t)

In the special case that the wavefunction is a quantum state with a definite energy value E, it has to look like:
f(x,t) = g(x)*exp(-i*E*t/(hbar)) , so
df/dt = (-i*E/hbar)*g(x)*exp(-i*E*t/hbar)) , and so:
df/dt = - (i*E/hbar)*f(x,t)
When you plug this into the time-dependent LHS, you get:
LHS = (i*hbar)*(df/dt)
= i*hbar*(-i)*E/hbar * f(x,t)
= E*f(x,t)
So if you take this special-case LHS, and equate it to the RHS, you get:

E*f(x,t) = (-(hbar)^2/(2m) Laplacian + V(x)) f(x,t)

Sorry to use all these equations, but you ARE asking about Schrödinger's equations!

The point is that the time-independent equation is a special case of the time-dependent equation, which you use to discover the specific values of E that will work - only a few values will work. It applies only when you assume that the time behavior is a complex exponential.

It is part of the folklore of physics that the SE is associated with skiing:
- First, when the original idea of the particle's wavelength was presented by de Broglie at a conference, Peter Debye commented, "Well, if we're going to say that particles behave like waves, isn't the grown-up approach to find an equation for the waves?" And then he and everyone else went skiing - except Schrödinger, who stayed home and found the wave equation (the time-dependent one, of course).
- Second, when the time came to write up the paper to fully lay out wave equation, Schrödinger went off on a skiing vacation with a young lady (who? unknown - but not his wife!) and during certain periods of the day, worked on these important papers. In particular, he generated solutions to many of the energy-value questions we still quote today (based on the time-independent SE) very easily - because a famous textbook in mathematical physics, by Courant & Hilbert, had essentially solved all these problems already! (They were just doing math, of course; they hadn't realized that Schrödinger was making up a theory that would employ their techniques so profoundly.)

I hope this provides some perspective.

2007-08-12 04:43:41 · answer #2 · answered by ? 6 · 1 0

Time-dependent is basically an academic exercise. He used the time-dependent equation to show that the wave equation is actually time-independent.

If you make the normal assumptions, time-dependent simplifies to time-independent. Time-independent is the form usually used for practical analysis.

2007-08-12 02:47:57 · answer #3 · answered by Anonymous · 0 1

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2016-11-12 02:47:15 · answer #4 · answered by ? 4 · 0 0

phisi(x,y,z,t)=0

partial differential equation,
d^2 (x)/dx^2 +d^2(y)/dy^2+d^2(z)/dz^2-Ud^2 (V)/dt^2=0
three dimentional wave equation.
z=rsinx,z=rcosy

2007-08-12 03:20:58 · answer #5 · answered by Anonymous · 0 1

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