I don't really know how to factor this thing! Can anyone please give me the steps on answering it?
2007-08-12 01:16:56 · 6 answers · asked by Chardy 2 in Science & Mathematics ➔ Mathematics
5 [ 25 x ² - (3y + 2) ² ]
5 [ 5x - (3y + 2) ] [ 5x + (3y + 2) ]
5 ( 5x - 3y - 2 ) ( 5x + 3y + 2 )
2007-08-16 00:15:29 · answer #1 · answered by Como 7 · 0⤊ 0⤋
125x^2 - 5(3y+2)^2
5{25x^2 - (3y +2)^2}....... since 5 is a factor of 5 and 125
5{(5x)^2 - (3y +2)^2}
now the part inside the big bracket is difference of two squares i.e. a^2 -b^2 = (a+b)(a-b)
5(5x - 3y -2)(5x +3y + 2)
2007-08-12 08:31:25 · answer #2 · answered by Southpaw 5 · 0⤊ 0⤋
500 -60y -40= 460-60y, steps, 125x2^= 125x4=500,now you multiply 3y+2 by 2^ whivh is 4, = 12y+ 8,and you multiply that by -5= -60y -40. So you have 500- 60y- 40,= 460-60y
2007-08-12 08:39:20 · answer #3 · answered by Dragon'sFire 6 · 0⤊ 0⤋
125x^2 - 5(3y+2)^2
5( 25x^2 - (3y+2)^2)
5(5x+3y+2)(5x-3y-2)
thats it
2007-08-12 08:51:32 · answer #4 · answered by Croasis 3 · 0⤊ 0⤋
5(25x^2-(3y+2)^2)=5(5x-(3y+2))(5x+(3y+2))
=5(5x-3y-2)(5x+3y+2)
2007-08-12 08:28:30 · answer #5 · answered by Anonymous · 0⤊ 0⤋
This equation isn't right
2007-08-12 08:29:24 · answer #6 · answered by ^-^ engineering student ! ^-^ 4 · 0⤊ 0⤋