Assuming that your "resistance free" length of copper had literally zero resistance, then all of the current would go through it, and none would go through any of your parallel resistors. In real life, however, this doesn't happen. Yes, less current (but still some small amount) would go through the resistors, as a length of copper would have some (non-zero) resistance.
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No, electricty doesn't follow "only the path of least resistance." It splits between all the available paths, with those of least resistance getting the most, and those of greatest resistance getting the least.
2007-08-11 16:50:46
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answer #1
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answered by skeptik 7
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If you have all resistors in parallel each resistor will pass the same amount of current and the voltage drop across each will be the source value. Now if you replace the last resistor with a wire and suppose that wire had the same resistance as the resistors there would be no change. If the wire were less resistance than the resistors more current would flow through the wire. The whole circuits total resistance cannot be greater than the resistor of least resistance which in this case is the wire. You would get no current flow through the resistors and all the current would pass through the wire.
2007-08-11 16:46:34
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answer #2
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answered by ? 3
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What is the resistance of the copper, and the total length? As well what is the value of the resistor you replaced it with?
You replaced a resistor, with a solid conductor. So more current or higher voltage will flow......Now what was the question?
2007-08-11 16:34:24
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answer #3
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answered by smittybo20 6
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a good resistor analogy is that of a motorway. think of of toll cubicles as resistors: assume your close by toll authority needs to collect seventy 5 cents from each and each automobile. it would desire to establish 3 successive toll cubicles, which each and each and each collect 25 cents, or it would desire to construct countless cubicles actual next to a minimum of one yet another (countless lanes), which each and each and each collect the total seventy 5 cents. the 1st case is somewhat like a chain configuration. Electrons (autos) are bogged down by each between the resistors (cubicles), and would pass very quickly interior the area between cubicles (modern interior the circuit is going up). the internet resistance, although, is somewhat severe! the 2nd case is like resistors in parallel. for the reason that each and each automobile could purely provide up as quickly as, and there is room for many autos to resign at as quickly as, the final site visitors congestion is low, and the autos will all could combat one yet another as quickly as the lanes merge back. modern maintains to be smaller, as does resistance. In doing any calculation, in basic terms keep in mind Ohm's regulation: V=IR. If resistance is going up, for consistent utilized voltage, the present could pass down. If voltage and resistance pass up proportionally, then modern could proceed to be an identical! In measuring voltage in the process a resistor, keep in mind Kirchoff's loop rule: the sum of all voltage drops in a loop could equivalent the sum of all voltage will boost (from batteries, inductors, and so on).
2016-12-11 17:25:42
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answer #4
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answered by boven 4
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This would be a perfect short circuit with no resistance if there is no circuit breaker, as the schematic shows and the power source is strong enough the copper wire will melt.
2007-08-15 14:20:10
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answer #5
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answered by johnandeileen2000 7
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if youre only adding distance in your circuit to one side, ( assuming im understanding your question correctly) then yes you would lose a certain amount of circuit loss depending on the length of conductor you add. all copper conductors have a certain amount of circuit loss across 2 points. this will be minimal at best if your circuit is only a few inches. if its a couple of miles such as a phone line is then the greater your loss will be. if your circuit is small as say a calculator. you probably couldnt even see it with a normal volt ohm meter
2007-08-11 16:34:12
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answer #6
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answered by fred bean 2
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