2007-08-11 15:09:11 · 4 answers · asked by DoWHATiDO 3 in Science & Mathematics ➔ Mathematics
You can solve this using the algebraic identity:
a^3 + b^3 = (a + b)(a^2 - ab + b^2)
We have x^3 + 64 = (x)^3 + 4^3
Here,
a = x
b = 4
So,
x^3 + 64 = x^3 + 4^3
= (x + 4)(x^2 - 4x + 16)
2007-08-11 15:26:06 · answer #1 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
x^3 = (x)^3
64 = (4)^3
=(x + 4)(x² - 4x + 16)
(a^3 + b^3) = (a + b)(a² - ab + b²)
(a^3 - b^3) = (a - b)(a² + ab + b²)
Same as above answer, very general
2007-08-11 22:17:10 · answer #2 · answered by Anonymous · 0⤊ 0⤋
x^3 = (x)^3
64 = (4)^3
=(x + 4)(x² - 4x + 16)
In general...
(a^3 + b^3) = (a + b)(a² - ab + b²)
(a^3 - b^3) = (a - b)(a² + ab + b²)
2007-08-11 22:14:55 · answer #3 · answered by forgetfulpcspice 3 · 0⤊ 0⤋
(x + 4)(x^2 - 4x + 16)
2007-08-11 22:14:42 · answer #4 · answered by mj_ 2 · 0⤊ 0⤋