in order to write this equation as a function of x f(x) we have to bring y on one side and x on the other (note, in order for the equation to be a function of x we need to keep an x in the equation.
5x - 6y = 6
5x - 6 = 6y
5x - 6/ 6 = y
let y = f(x)
f(x) = (5x - 6)/6
f(x) = (5x/6) - 1 <-- another way to write the equation
everyone who answered above me is wrong except for mj_, he got it right.
also...function of x means that you only want an x variable in your equation...
added info: if you wanted it to be a function of y, f(y) it would be: f(y) = (6y - 6) / 5
2007-08-11 15:00:19
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answer #1
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answered by Anonymous
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rewriting some thing as a "function of x" ability that could desire to isolate the different variables, as a effect y. this way, if we plugged in a cost of x, we'd get a effect for y. for this reason, -5x - 6y = -12 => -6y = -12 + 5x => y = (-12 + 5x)/(-6) => y = 2 - 5/6x => y = 2 - .eighty 3 x or f(x) = 2 - .83x - y
2016-10-10 00:57:36
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answer #2
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answered by lishego 4
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You first must put the x on the other side of the y. Subtract 5x and the eq become -6y = 6 - 5x. Now divide all by -6. Equal y= -1+ 5/6x. Now rewrite. y= 5/6x -1
2007-08-11 14:59:27
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answer #3
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answered by Diego E 1
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y has to be the subject.
6y + 6 = 5x
6y = 5x - 6
y = (5/6)x - 1.
So f(x) = (5/6)x - 1
2007-08-11 14:56:41
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answer #4
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answered by mj_ 2
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5x -6y = 6
Add 6y to both terms:
5x -6y+6y = 6+6y
5x=6+6y
Divide both terms by 5
5x/5=(6+6y)/5
x=(6+6y)/5
2007-08-11 14:58:01
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answer #5
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answered by Kant 1
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5x - 6y = 6
5x = 6y + 6
x = (6/5)y + (6/5)
2007-08-11 14:57:20
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answer #6
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answered by Chris2457 2
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5x-6y=6
5x=6+6y
x = (6+6y) / 5
2007-08-11 14:57:28
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answer #7
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answered by Anonymous
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5x - 6y = 6
5x -6 = 6y
y = (5x - 6)/6 = 5x/6 - 1
2007-08-11 14:57:09
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answer #8
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answered by mechnginear 5
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f(x) = (6y+6)/5
2007-08-11 14:55:48
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answer #9
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answered by Maverick 7
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5x - 6y = 6
6y = 5x - 6
y = (5x - 6)/6
Let y = f(x)
This gives,
f(x) = (5x - 6)/6
f(x) = (5x/6) - 1
2007-08-11 15:34:25
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answer #10
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answered by Akilesh - Internet Undertaker 7
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