help solving problem? 10 easy points?

Question

ok, this is a really easy math question, but my brain is FRIED so i'd highly appreciate it if someone could provide a correct answer and how you got to that answer. ok the problem is
x^2 + 3x = -2
please, if you know the answer to this problem, answer this question. i PROMISE i'll give you points as soon as you answer.
thanks.

Answer 1

get everything on one side of the equation:
x^2 + 3x +2 =0

now factor
(x+2)(x+1)=0

set each part =0
x+2=0 or x+1=0

x=-2 or x=-1

Answer 2

OK we need to put this equation in a familiar form called quadratic. Where we have some x squared plus some x plus a number is equal to zero. so this becomes:

x^2 + 3x +2 = 0 after you add +2 to both sides of the equation.

Next to solve for x you need to factor. If it can be done like this:

(x+1)(x+2)= 0

now you have two multiplied values giving a zero for an answer, then one of them has to equal zero because anything times a zero equals zero.

Now if the first is zero then x+1=0 so x= -1
that makes the first term a zero and it doesn't matter what the other is. OR
x+2=0 then x = -2

and the second term which is a zero multiplied by whatever the first term is still ends up being equal to zero. So we say:

x=-1 or x=-2
x can be -1 or -2.

Note x can have two values because the highest power x had in the equation was a 2. So we say this is an equation of the second order. Or quadratic.

Answer 3

x ^2 + 3x +2 = 0

(x + 2)(x +1) = 0

x + 2 = 0 => x = - 2

x + 1 = 0 => x = -1

Answer 4

x^2 + 3x + 2 = 0

(x+1)(x+2) = 0

x = -1 or -2

Basically this is the factoring method.

3 = -(sum of roots)

2 = (product of roots)

If you wish to use completing the square method that would be fine too.

x^2 + 3x = -2

3 = b

Add b^2/4 on both sides.

x^2 + 3x + 9/4 = 1/4

You can factor this into:

(x+b/2)^2 = 1/4

b = 3

(x+1.5)^2 = 1/4

x + 1.5 = 0.5

x + 1.5 = -0.5

x = -1

x = -2

I got b = 3, because a normal quadratic equation would have been written this way:

ax^2 + bx + c = 0

Answer 5

X^2+3x + 2 = 0
or, X^2 + x + 2x + 2 = 0
or, X(X + 1) + 2(X + 1) = 0
or, (X+1)(X+2) = 0
so, X = -1 or -2

Answer 6

x^2 + 3x = -2
so
x^2 + 3x + 2 = 0
Try factor it
( x + 2) (x + 1) =0
it factors,
so
x +2 =0 x= - 2
or
x + 1 = 0 x = -1

Ans x= 2 or x = -1

Answer 7

x^2+3x+2=0
(x+2)(x+1)=0
x+2=0 orx+1=0
x=-2 x=-1

Answer 8

x^2 + 3x + 2 = 0
Then use the quadratic equation:
(-b +- root(b^2-4ac)) / 2a
= (-3 +- root(3^3-4(1)(2))) / 2(1)
= (-3 +- root(1)) / 2
= (-3 +- 1) / 2
= (-3+1)/2 and (-3-1)/2
= -2/2 = -1
= -4/2 = -2

So answers are -1 and -2

Answer 9

x^2+3x=-2
Move all terms to the left,
x^2+3x+2=0
Factor and solve for x
(x+1)(x+2)=0
So, x=-1 and x=-2, two solutions.

Answer 10

x^2+3x= -2
x^2+3x+2=0
x^2+x+2x+2=0
x(x+1)+2(x+1)=0
(x+1)(x+2)=0
x= -1 or -2