Are you a teacher? Because if you are, can you give me the answers that way I can ask my mom that and be able to figure it out while having the right answer. Can you teach me and help me with the answer? please.
2007-08-11 11:00:36
·
answer #1
·
answered by <3 to live life 3
·
0⤊
0⤋
Start with the 4. 4 equals 2 squared as well as 2+2. Then you take the 3/2. 3 halves is what ex-wives will take if you get married and seperated 3 times. So 3/2 & the 4 gives you 16. Good luck.
2016-05-20 00:04:29
·
answer #2
·
answered by ? 3
·
0⤊
0⤋
First we want to simplify this expression, by rewriting division as negative exponents. Negative exponents are much easier to differentiate. Write the problem as:
(x^-2 - 3x^-4)(x + 5x^3)
You could use the chain rule at this point, but since it is a simple binomial, I would distribute to get:
x^-1+ 5x - 3x^-3 -15x^-1
Simplify like terms to get:
-14x^-1 + 5x - 3x^-3
Finally take the derivative, by multiplying the exponent by the coefficient and subtracting one from the exponent:
14x^-2 + 5 + 9x^-4
The derivative may be rewrote as positive exponents, as:
14/x^2 + 5 + 9/x^4
2007-08-11 11:16:55
·
answer #3
·
answered by neil 2
·
0⤊
0⤋
I multiplied this out, rather than use the product rule and I got 5x-2x^-1-3x^-3. If I then differentiate I get 5+2x^-2+9x^-4.
Is there an error in the form of your question?
However, you would do the product rule this way, where the apostrophe stands for the derivative of the function:
(x^(-2)-3x^(-4))*(x+5x^3)'+(x^(-2)-3x^(-4))'*(x+5x^3)
since the derivative of a sum is the sum of the derivatives you then solve inside the parenthesis:
(x^(-2)-3x^(-4))*(1+15x^2)+(-2x^(-3)+12x(-5))*(x+5x^3)
Hopefully it then reduces down if I did it right. This is quite difficult to do while typing rather than on paper.
It is blocking my long lines of typing so I am going to break the above lines into multiple lines for readability.
(x^(-2)-3x^(-4))*(x+5x^3)'
+(x^(-2)-3x^(-4))'*(x+5x^3)
differentiating
(x^(-2)-3x^(-4))*(1+15x^2)
+(-2x^(-3)+12x(-5))*(x+5x^3)
I will let you then do the product and addition part.
I do not have a sheet of paper and it is too easy to make a mistake here.
2007-08-11 11:07:07
·
answer #4
·
answered by OPM 7
·
0⤊
0⤋
you simply take the coefficient of the quotient of the first variable in each expressin and divide it by the number of quantities there are in the product.
2007-08-11 11:02:27
·
answer #5
·
answered by Shy Guy 4
·
0⤊
0⤋
what do you mean?
you want the steps of how you get to the answer or what?
and what do you mean by formula?
2007-08-11 11:00:15
·
answer #6
·
answered by Frank 3
·
0⤊
0⤋
learn something your actually going to use in real life.....computers do these tinings for us now !
2007-08-11 10:58:17
·
answer #7
·
answered by Anonymous
·
0⤊
1⤋
huh?
2007-08-11 10:57:43
·
answer #8
·
answered by foolish_love_haze@yahoo.com 2
·
0⤊
0⤋
what?
2007-08-11 10:57:05
·
answer #9
·
answered by Jessica P 1
·
0⤊
0⤋