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I need to know the step of how you did it.
The formula is f(x)g'(x) + g(x)f '(x)

2007-08-11 10:52:59 · 9 answers · asked by ? 1 in Science & Mathematics Mathematics

This is a calculus question.

formula is

f(x) = g'(x)f(x) + f"(x)g(x)

I need to know how you did it.

2007-08-11 11:01:36 · update #1

9 answers

Are you a teacher? Because if you are, can you give me the answers that way I can ask my mom that and be able to figure it out while having the right answer. Can you teach me and help me with the answer? please.

2007-08-11 11:00:36 · answer #1 · answered by <3 to live life 3 · 0 0

Start with the 4. 4 equals 2 squared as well as 2+2. Then you take the 3/2. 3 halves is what ex-wives will take if you get married and seperated 3 times. So 3/2 & the 4 gives you 16. Good luck.

2016-05-20 00:04:29 · answer #2 · answered by ? 3 · 0 0

First we want to simplify this expression, by rewriting division as negative exponents. Negative exponents are much easier to differentiate. Write the problem as:
(x^-2 - 3x^-4)(x + 5x^3)

You could use the chain rule at this point, but since it is a simple binomial, I would distribute to get:
x^-1+ 5x - 3x^-3 -15x^-1

Simplify like terms to get:
-14x^-1 + 5x - 3x^-3

Finally take the derivative, by multiplying the exponent by the coefficient and subtracting one from the exponent:
14x^-2 + 5 + 9x^-4

The derivative may be rewrote as positive exponents, as:
14/x^2 + 5 + 9/x^4

2007-08-11 11:16:55 · answer #3 · answered by neil 2 · 0 0

I multiplied this out, rather than use the product rule and I got 5x-2x^-1-3x^-3. If I then differentiate I get 5+2x^-2+9x^-4.

Is there an error in the form of your question?

However, you would do the product rule this way, where the apostrophe stands for the derivative of the function:

(x^(-2)-3x^(-4))*(x+5x^3)'+(x^(-2)-3x^(-4))'*(x+5x^3)

since the derivative of a sum is the sum of the derivatives you then solve inside the parenthesis:

(x^(-2)-3x^(-4))*(1+15x^2)+(-2x^(-3)+12x(-5))*(x+5x^3)

Hopefully it then reduces down if I did it right. This is quite difficult to do while typing rather than on paper.

It is blocking my long lines of typing so I am going to break the above lines into multiple lines for readability.

(x^(-2)-3x^(-4))*(x+5x^3)'
+(x^(-2)-3x^(-4))'*(x+5x^3)

differentiating
(x^(-2)-3x^(-4))*(1+15x^2)
+(-2x^(-3)+12x(-5))*(x+5x^3)

I will let you then do the product and addition part.

I do not have a sheet of paper and it is too easy to make a mistake here.

2007-08-11 11:07:07 · answer #4 · answered by OPM 7 · 0 0

you simply take the coefficient of the quotient of the first variable in each expressin and divide it by the number of quantities there are in the product.

2007-08-11 11:02:27 · answer #5 · answered by Shy Guy 4 · 0 0

what do you mean?
you want the steps of how you get to the answer or what?
and what do you mean by formula?

2007-08-11 11:00:15 · answer #6 · answered by Frank 3 · 0 0

learn something your actually going to use in real life.....computers do these tinings for us now !

2007-08-11 10:58:17 · answer #7 · answered by Anonymous · 0 1

huh?

2007-08-11 10:57:43 · answer #8 · answered by foolish_love_haze@yahoo.com 2 · 0 0

what?

2007-08-11 10:57:05 · answer #9 · answered by Jessica P 1 · 0 0

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