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Express as a unit rate 19 yards in 2.5 minutes.
can u explain it to me too plz.

thnk u so much

2007-08-11 10:21:32 · 6 answers · asked by golden<3 2 in Science & Mathematics Mathematics

6 answers

Unit rate means Changingin amount with respect to a changing unit.. in this case.. 19 yards may change to some other higher value if the time is now 3 minutes or more..
for this question,
Simply divide 19 yards by 2.5 minutes, u'll get 7.6 yards in 1 minute.
so the answer is 7.6 yards / minute (this is rate)
also, one yard is 3 feet and 1 minute is 60 seconds.. so the the answer can also be
= (19*3) / (2.5*60)
= 57 / 150
= 0.38 feet / second
or
= 4.56 inch / second
I hope this works
IM or email if u need more help
best of luck

2007-08-11 10:32:22 · answer #1 · answered by Aflaah 2 · 1 0

First you need to understand what a unit rate is. A unit rate is when something is expressed "per unit". For example, if there is a bag of pop corn that weighs 8 oz. and it costs 4 dollars, then the unit price (price per unit) is $.50. In this case the unit is minutes (because rate is time) So you would need to find how many yards in 1 minute. The algebraic equation for this would be 19y = 2.5m. You would want to isolate the m so you'd need to divide both sides by 2.5 and you would get 7.6y = m, so that tells you that there would be 7.6y per minute.

2007-08-11 17:31:26 · answer #2 · answered by Anonymous · 1 0

So many complicated answers!

Rate is a distance per unit of time:

You have: 19 yards per 2.5 min's.

19 yards/2.5 minutes = (19/2.5) yards/minute = 7.6 yards per minute.

It just means that you can travel 7.6 yards each minute.

2007-08-11 17:42:26 · answer #3 · answered by Anonymous · 1 0

How many yards per minute?
Unit rate is # of A per 1 unit of B

2007-08-11 17:26:22 · answer #4 · answered by John R 7 · 1 0

in this case, yd/min, so 19/2.5 = 7.6 yd/min. This means that in each minute 7.6 yards are gained

2007-08-11 17:24:18 · answer #5 · answered by John V 6 · 1 0

rate = 19 yards / 2.5 sec
. . . = 7.6 yds / sec

2007-08-11 17:25:42 · answer #6 · answered by CPUcate 6 · 1 0

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