If one is given, sin^2x one can change that into (1-cos^2x). If one is given sin^4x one can change that into (1-cos^2x)^2. So if one was given sin^5x, would one change that into (1-cos^2x)^5/2...if not plz explain what one must do to change sin^5x into the (1-cos^2x) form. Therefore, what would be the general rule?
2007-08-11 03:14:17 · 4 answers · asked by SSj4Monkey 1 in Science & Mathematics ➔ Mathematics
sin(^5) x
= (sin^(4) x) (sin x)
= (sin ² x) ² (sin x)
= (1 - cos ² x) ² (sin x)
2007-08-16 00:07:31 · answer #1 · answered by Como 7 · 3⤊ 0⤋
sin^5x â (1-cos^2x)^5/2 because LHS can be negative, and RHS must be positive.
If you have to write sin^5x into the (1-cos^2x) form, then here is one way:
sin5x = (1-cos^2x)^5/2, if sin5x ⥠0
sin5x = -(1-cos^2x)^5/2, if sin5x < 0
2007-08-11 04:35:16 · answer #2 · answered by sahsjing 7 · 3⤊ 0⤋
When the power is odd, just make it even.
So, sin^5x = (sinx)(sin^4x) = (sinx)((1 - cos^2x)^2)
2007-08-11 03:44:54 · answer #3 · answered by seminewton 3 · 1⤊ 0⤋
go to the website
2007-08-16 04:48:23 · answer #4 · answered by Anonymous · 1⤊ 2⤋