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i am standing on a flat piece of land, i will be able to see 50% of the sky...... When i stand 2000km above the level of land, how many percent of sky can i see???????

2007-08-10 21:19:25 · 11 answers · asked by suseendar 1 in Science & Mathematics Mathematics

11 answers

Well, I'm not sure how to answer that, because I think the first premise (you can see half the sky) is false.

EDIT:
Now that I've thought about it a little more, I realize that I just can't solve it myself (at least not in a reasonable amount of time). The solution will require some pretty tricky integration. Draw a sphere (representing earth) surrounded by a larger sphere (arbitrarily representing the "edge" of the sky). Now find how far the horizon is from your standing vantage point (probably about 2 m above the surface). I provided a calculator for this purpose in my sources. Draw a line connecting your position to the horizon point (the horizon is actually a circle, but on paper, it will be 2 points, one on either side of you) and extend the line until it reaches the sky sphere. Everything in this sort of inverted cone is what you can see. That's the integral you need to do. Now repeat the process for 2000 km above the surface. Finally, set the ratio of the second integral to the first integral equal to x / 50 and solve for x. Good luck! (cool problem, by the way)

2007-08-10 21:30:47 · answer #1 · answered by Anonymous · 0 0

start with the fact that the radius of earth is 6,378.135 km.
Now, when standing on the surface of the earth and looking up at the sky your height becomes negligible so from a side view you are a don't on a point of an arc of a circle. If you draw a tangent line to this arc that passes through you as a point on the arc this is your field of view from that point it is a half a circle or an arch of a central angle of 180 deg which is 50% of the sky. Now as you move further abve the earth your view of the sky increases linearly with the vertical distance you move above your previous point. i.e the central angle of your view of the sky increases past 180 deg and the arc legth of your available view increases. the best mathematical relationship that would describe this amount is:
PSV= (ABV)/360 * 100
ABV = 360 - 2(Arcsin (r+d)/r)
Where % of sky view = PSV ABV = angle behind viewer's horizon. r = raduis of earth and d= observers distance above earth's surface.

PSV= 50% when d=0 and r = 6,378.135 km ABV= 180 deg

Now at 2000 km ABV =360 - 99.155 = 260.845 deg
and his/her angle of view of the sky is:
PSV= 260.845/360*100= 72.456 %

2007-08-10 23:22:28 · answer #2 · answered by 037 G 6 · 0 0

An exact answer will require some integral calculus. Solve for the distance to the horizon using h(r+h) = D^2, where r is the radius of the earth, h is your height above the surface, and D is the distance to the horizon. You can then calculate the angle by which the horizon is below the horizontal. Use this as one of the limits on a definite integral (the other limit being vertical) to calculate and sum the area of rings of constant radius (from your feet) as the angle changes. Don't forget to allow for the inclination of the rings -- use Pythagoras to get the ring dimensions. (It's the same thing as measuring arc length of a curve.)

2007-08-10 21:28:33 · answer #3 · answered by Anonymous · 0 0

The 2000 km above the level of land is in space.You can see
97% sky.

2007-08-11 03:10:13 · answer #4 · answered by Anonymous · 0 0

I majored in the two physics and math. Math is a gadget, a language. Physics makes use of the maths to sparkling up issues and describe the universe. math is the how and physics is the why. I agree that physics does no longer be what it rather is without math. attempt working circuit diagnosis without using Kirkoff's regulations in math variety. you may desire to describe what you assume to happen according to test, yet you may desire to no longer are anticipating what numbers you may get. How would desire to I rather have extrapolated an entire magnetic field in my examine from a pair numbers if we did no longer have the equations to describe what could be happening. Physics and philosophy could have plenty greater in common. Math exists in spite of physics. The language of God Himself. you may run by organic logic and discover the solutions to many precis questions. i've got seen the data that a million=a million. in case you delve too far into math without reason (physics) you would be pushed insane.

2016-12-11 16:51:29 · answer #5 · answered by ? 4 · 0 0

The earth curves away at 100 feet per 15 miles of distance
1250 miles up line if site strikes the ground 185 miles away

1250 / 185 Is your slope convert to degrees * 2 + 180
This is your cone now calculate surface area of the sphere inside and out side the cone.

2007-08-10 21:28:38 · answer #6 · answered by Anonymous · 0 0

What an interesting question...I not very sure. but I think the answer is 50% as the sky is so huge, even if u stand 5000km above the level of land , it is still 50%

2007-08-10 21:43:07 · answer #7 · answered by Anonymous · 0 1

A question about solid angle.

The mean radius of earth is 6373 km.
Length of the tangent segment from u to earth = √[(8373)^2 – (6373)^2] = 5431 km

The sky be blocked by earth is a spherical cap of a sphere with radius of 5431 km.

The cone has a apex angle of 2θ
θ = arc tan (6373 / 5431) = 50 degree

% of Sky be seen = 1 – [2π(1 – cosθ) / 4π] = 82%

2007-08-10 22:41:25 · answer #8 · answered by Anonymous · 0 0

it depends.. what do you call a sky..
if it is the plue sky then..
as blue is the ozone gas and it is present above 1500 km from earth so
it will be down you..
or you will be able to see it 100 %
and if the sky is above where starts are there..
then there is no way you can measure

2007-08-10 21:26:57 · answer #9 · answered by usman 3 · 0 1

Sorry, I'm not here to help you. I just want to say that I feel your pain!

Physics and math...UGH!

2007-08-10 21:21:58 · answer #10 · answered by Anonymous · 0 4

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