English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

(6x-1)/5- 2x/3=3

2007-08-10 17:26:03 · 10 answers · asked by Anonymous in Science & Mathematics Mathematics

10 answers

(6x-1)/5- 2x/3=3

multiply 15 to each number
3(6x-1) - 5(2x) = 3(15)
18x - 3 - 10x = 45
8x = 45 + 3
8x = 48
x = 48/8
x = 6

2007-08-10 17:31:11 · answer #1 · answered by wow 2 · 0 0

(6x-1)/5-2x/3=3 Multiple both sides by 3 =
3(6x-1)/5- 2x=9 Multiple both sides by 5=
3(6x-1)-10x=45 solve for X =
18x-3-10x=45
18x-10x=48
8x=48
x=6
Plug 6 into the equation you get
6(6)-1/5-2(6)/3=3 =
36-1/5 - 12/3= 3 =
35/5 -12/3=3 =
7-4=3 =
3=3

2007-08-10 18:01:11 · answer #2 · answered by Sharkboy 1 · 0 0

step 1: first find a common denominator (for simplicity, use 15).

step 2: multiply by the common denominator.
15 {(6x-1)/5- 2x/3=3} becomes [3*(6x-1)] - [5*(2x)] = 15*3 which turns into 18x - 3 - 10x = 45

step 3: combine like terms by adding 3 to both sides.
18x - 3 - 10x +3 = 45 + 3 becomes 18x - 10x = 45 + 3 which turns into 8x = 48

step 4: solve for x by dividing each side by 8.
8x / 8 = 48 /8 becomes x = 6

to check
step 1: substitute 6 wherever x appears, into the original problem.
(6x-1)/5- 2x/3=3 becomes [(6*6) - 1]/5 - (2*6)/3 = 3
and u get that (36-1)/5 - 12/3 = 3
step 2: 35/5 - 12/3 = 3
step 3: 7 - 4 = 3
step 4: 3 = 3
therefore, x = 6 is the answer

2007-08-10 17:41:30 · answer #3 · answered by pillows 1 · 0 0

How I would go about solving this problem would be to get rid of the fractions, even though I love them (yeah. I'm weird). To get rid of them, you need to multiply the whole equation by both of the denominators (5 and 3), to save a step, I'm going to multiply through by both of them at the same time, the 5's will cancel out in the first fraction and the 3's in the second leaving you with:

3(6x-1) -5(2x) =3*5*3 now simplify it (multiply)

18x-3 -10x = 45 combine like terms:

8x - 3 = 45 add 3 to both sides:

8x = 48 divide through by 8 to find the value of x:

x=6

to check it, plug 6 in for x in the original equation:

(6*6-1)/5 - 2(6)/3 = 3

(36-1)/5 - 12/3 = 3

35/5 - 4 = 3

7 - 4=3

3=3 it checks =)

2007-08-10 17:33:20 · answer #4 · answered by sarajschryver 2 · 0 0

so 6x/5 - 1/5 -2x/3 = 3
get everything over a common denominator (15)
18x/15 - 3/15 - 10x/15 = 45/15

8x/15 = 48/15

8x = 48

x = 6

then replace x with 6 in the original equation and if it is correct then u hav the rite answer.

(6x6 - 1)/5 - 2x6/3 = 3

35/5 - 12/3 =3

7 - 4 = 3

which it does so RHS = LHS so the answer x=6 is correct!

2007-08-10 17:30:15 · answer #5 · answered by Anonymous · 1 0

3(6x - 1) - 10x = 45
18x - 3 - 10x = 45
8x = 48
x = 6
Check
(36 - 1) / 5 - 12 / 3 = 7 - 4 = 3 (as required)

2007-08-10 19:50:59 · answer #6 · answered by Como 7 · 0 0

you multiply both sides by 5*3 =15
3*(6x-1)-10x=45
18x-3-10x=45
8x=48

x=6

and replacing x by 6 check below

(36-1)/5-12/3=7-4=3

2007-08-10 17:33:43 · answer #7 · answered by maussy 7 · 0 0

(6x-1)/5- 2x/3=3
3(6x-1) - 5(2x) = 15(3)
18x - 3 - 10x = 45
8x = 48
x = 6

2007-08-10 17:46:55 · answer #8 · answered by vlee1225 6 · 0 0

first of all, divide the two components by way of -3. x=-9 you could verify by way of plugging -9 back into the equation for x to verify if it extremely does artwork. -9 x -3 = 27. subsequently, -9 is the right fee for x.

2016-11-12 00:20:57 · answer #9 · answered by ? 4 · 0 0

x=6;and it verifies the answer

2007-08-10 17:56:41 · answer #10 · answered by Zinda 1 · 0 0

fedest.com, questions and answers