Is this correct??

Question

(x)=-x^3-x^2+2x-8 find f(-1),f(0),f(2)

f(-1)=(-1)63-(-1)^2+2(-1)-8
-3-2+-2-8
answer -15

f(0)^3-(0)^2+2(0)-8
0-0+0-8
answer -8

f(2)^3-(2)^2+2(2)-8
8-4+4-8
answer is 0

Answer 1

f(-1) = -(-1)^3 - (-1)² + 2(-1) - 8
f(-1) = 1 - 1 - 2 - 8 = -10

you do NOT multiply the base by the exponent.

f(0) = -8

f(2) = -(2^3) - 2² + 2(2) - 8
f(2) = -8 - 4 + 4 - 8
f(2) = -16

Answer 2

f(-1)=-(-1)^3-(-1)^2+2(-1)-8
=-(-1)-(1)-2-8
=1-1-10
=-10
f(0)=-(0)^3-(0)^2+2(0)-8
=-8
f(2)=-(2)^3-(2)^2+2(2)-8
=-8-4+4-8
=-16 ans so your only 2nd answer is correct.

Answer 3

f(-1)= -(-1^3) - (-1^2) +2(-1)-8= -(-1)-(1)-2-8= 1-1-2-8 = -10 Your mistake is when you elevate one to the third and one squared, you wrote (-1)^3=3 and (-1)^2=2

f(0)= 0-0+0- 8 =-8 Correct.

f(2) = -(2^3)-(2^2)+2(2)-8=-8-4+4-8=0 Correct.

Answer 4

f(-1)=-1-1-2-8=-12
not -15
f(0), f(2 ) are correct.