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Very tough rules question - first right answer with explanation gets the points.

2007-08-10 05:25:25 · 21 answers · asked by artistictrophy@sbcglobal.net 4 in Sports Baseball

Ok folks - has nothing to do with a man being thrown out at home - that would not be a base hit, it would be a fieilder's choice. Good try though

2007-08-10 05:41:45 · update #1

21 answers

A team can get as many as 6 hits in an inning and still not score a run.

Example:

Each of the first 2 batters get singles but are thrown out trying to stretch them into doubles.

The next 3 batters all hit singles to load the bases.

The 6th batter hits a ball that hits one of the runners in fair territory. That runner is ruled out but the batter is credited with a hit. No run scores.

2007-08-10 05:33:10 · answer #1 · answered by Anonymous · 6 1

This is a great question..lol

I'm going to guess 3. We'll assume that the first 3 batters all hit singles to get on base and advance the runners loading up the bases and creating a force out at the plate.

The next three batters put the ball into play in the infield and the play is made at the plate giving the base to the batter. This type of play however would be scored as a "Fielders Choice" thus the batters making it to first would not get credited with a hit. So, I'll go with 3...not 6.

2007-08-10 05:40:13 · answer #2 · answered by tg315 5 · 0 2

Bryan's got it: six.

First batter gets a non-HR hit, and is put out on bases (thrown out stretching, caught stealing, picked off -- whatever).

Second batter essentially repeats first batter.

Third, fourth, fifth batters single, loading the bases.

Sixth batter slaps a grounder which hits one of his runner teammates in fair territory (so most likely the guys on first or second) before a defensive player has had a chance to make a play on the ball. Plunked runner is out, batter is awarded a single, no baserunners advance unless forced by the batter-runner, three outs, three left on, no runs.

Wow, actually haven't seen this one in about a month.

2007-08-10 08:29:06 · answer #3 · answered by Chipmaker Authentic 7 · 0 0

Six; first on three singles then the next three batters getting a hit by having the ball hit the runner at 3rd(only if he is in fair territory, then he's out, no run scores and the batter is credited with a basehit) Viola! six straight hits, no runs scored and out of the inning.

2007-08-10 06:50:08 · answer #4 · answered by Kelly P 4 · 1 0

I am guessing 6 - First two batters get base hits and get caught stealing or thrown out trying to stretch it to a double. (2 hits, 2 outs, 0 runs) Next three batters get base hits, but no one scores (5 hits, 2 outs, 0 runs, bases loaded.) Next batter gets a base hit, but the runner from third misses home plate before leaving the field, therefore he's out. (6 hits, 3 outs, 0 runs).

2007-08-10 05:36:02 · answer #5 · answered by Double A 4 · 0 1

1st batter - Hits triple caught on the plate for interior the parker. a million-a million out 2d batter- Hits triple caught on the plate for interior the parker. 2-2 out third batter- Hits a single. Runners on first 3-2 out 4th batter- Hits a single. Runners on first and 2d. 4-2 out. 5th batter- Hits a single. Basesloaded 5-2 out. 6th batter- Hits the ball and hits a runner, the runner is out and he's credited with a single. Hits 6. Runs scored-0. Edit- King James beats me to it yet technically then thats 2 strategies slightly diverse which shows how.

2016-11-11 23:03:52 · answer #6 · answered by ? 4 · 0 0

6, after the bases are loaded from 3 singles, the next three hits go into the out field but since they are flyball the runners hold at third the ball drops and they get thrown out at home. if the hits stayed in the infield they would be ruled fielders choice and not count as a hit. i dunno if thats right but thats all i could think of.

2007-08-10 05:37:04 · answer #7 · answered by George C 4 · 0 1

I'm going to say 6 as well.

Single -1
single - 2
single - Bases loaded - 3
Pitcher picks runner off of 3rd base - one out
single - bases loaded - 4
Pitcher picks off runner on 3rd - two outs
single - bases loaded - 5
single - runner on 2nd passes runner on 3rd before they reach home. Batter credited with a single. Runner called out.
No runs, six hits.

2007-08-10 06:09:27 · answer #8 · answered by Anonymous · 1 0

6 Single, single, single, bases loaded. Single runner from third has base running error thrown out at home. Repeat 2 more times. 6 Base hits, 3 errors, no runs.

2007-08-10 05:32:03 · answer #9 · answered by Trish 3 · 0 2

3 is the correct answer. That would load the bases, then all other "hits" with no runs scoring (runner out at home) would be fielder's choice, not base hits.

2007-08-10 05:35:12 · answer #10 · answered by wick7998 3 · 0 2

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