You have enough information to solve for the slope, which is the only thing you still need. Just plug in our point and intercept into the equation:
y = mx + b
==> plug in numbers
5 = m(-2) - 4/5
==> add 4/5 to both sides
29/5 = m(-2)
==> divide by -2 on both sides
-29/10 = m
Now, we have our slope and y-intercept, so we can plug it into the equation and we have:
y = (-29/10)x - 4/5 ... ANSWER
2007-08-10 04:55:31
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answer #1
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answered by C-Wryte 4
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so if the y intercept is -4/5 then the point is (0,-4/5) as well as the point (-2,5)
use the formula m = (y2-y1)/(x2-x1)
and this gives u the gradient.
so m = (5+4/5) / (-2-0)
dont hav calculator so not sure what that equals.
then u use the equation of a straight line, y=mx+c
so using the point (-2,5) u get:
5=m(-2) +c (u need to work out m above n use it in the formula)
then solve for c and that is ur constant value.
so the equation is y=mx + c (and u use the m and the c u hav worked out in the equation)
2007-08-10 05:02:02
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answer #2
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answered by Anonymous
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In slope-intercept form the equation is
y = (slope)*x + intercept
y = mx + b
You have the intercept, -4/5, so plug in the coordinates of the other point and solve for the slope:
5 = m(-2) + -4/5
25/5 = m(-2) + -4/5
29/5 = m(-2)
-29/10 = m
y = (-29/10)x - 4/5
2007-08-10 05:02:18
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answer #3
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answered by Philo 7
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coz u know the intercept u know that y=mx-4/5
then substitute in the point (-2,5) into that and u get 5=-2m-4/5
which means that 2m = -4/5 + 5 which simplifies to m = 21/10
so the equation of the line is y=21/10x-4/5 and if you multiply all that by 10 the equation would be 5y=21x-4 and that makes it look a whole lot more nicer so i think the answer is 10y=21x-8
2007-08-10 05:01:32
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answer #4
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answered by Anonymous
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It is simply a system of equation
The equation of the line is y = ax + b
You have two points (-2,5) and (0, -4/5), because x=0 on the y-intercept
plug in the second point in the line equation and you get
-4/5 = b
Therfore y = ax - 4/5. Now plug in the values of the other point and you get 5 = -2a -4/5 or a = -29/10 = -2.9
so the line is y = -2.9x - 4/5 or y = -2.9x - 0.8
2007-08-10 04:58:51
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answer #5
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answered by Christophe G 4
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If the line has a y-intercept of -4/5, it passes through the point (0,-0.8). It also passes through (-2,5). The slope of the line is
m = (y2 - y1) / (x2 - x1)
It doesn't matter whether (0, -0.8) is point 1 or vice versa.
The equation of the line is
y = m x + b, where m is calculated above, and you were given b, the y-intercept.
Go for it.
2007-08-10 05:00:19
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answer #6
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answered by anobium625 6
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well, you know one of your points is (0, -4/5) or (0, -.8)and an another is (-2,5), so the slope of the line is (y-y1)/(x-x1)
= (5- -.8)/(-2 - 0) = 5.8 / -2 = -2.9
so this is your slope m in the equation y = mx + b.
b is the y-intercept which they already gave you, so you know the equation has to be:
y = -2.9x - .8
2007-08-10 04:57:40
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answer #7
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answered by Jon G 4
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To verify what everyone else has written:
I also got y = (-29/10)x - 4/5. (using the y=mx+b format)
this is because you know that b is -4/5 because that is given and to find the slope you use the formula [(y2-y1)/(x2-x1)] and you get -29/10 as your M.
Simply adding these numbers in the formula you get y = (-29/10)x - 4/5
Hope this helps.
2007-08-10 05:22:10
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answer #8
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answered by Brad H 2
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Yea dude this question isnt too difficult you can do it. if you want to find the slope, just know if a point is a Y INTERCEPT the 'x' value HAS to be zero ... right? then no prob, you have two points now u have (0,-4/5) and (-2,5) *<-given*... haha this is gonna be my answer to your question if u need more tell me i cant answer it mannnn~! that ruins the necessary struggles you need.
2007-08-10 05:04:35
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answer #9
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answered by David N 1
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Y=mX + C, find m (slope) from the given info, and you can have the equation.
You can find any text book on Coordinate Geometry to do this kind of math.
2007-08-10 04:59:33
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answer #10
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answered by FunnyGuy 2
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