help help needed.?

Question

Simplify this question and show detailed working in how you derived at your answer.
Thank you very much for your help.

Q) (2x^3)^5 / 3xy devide x / 2y^2

Answer 1

(((2*x^3)^5)/(3*x*y)) / (x/(2*y^2))
= (((2^5*x^(3*5))/(3*x*y)) / (x/(2*y^2))
= ((32*x^15)/(3*x*y)) / (x/(2*y^2))
= ((32*x^15)/(3*x*y)) * ((2*y^2)/x)
= ((32*x^14)/(3*y)) * ((2*y^2)/x)
= ((32*x^14)*(2*y^2)) / (3*y*x)
= ((32*x^13)*(2*y)) / 3
= (64/3) * (x^13) * y
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Answer 2

I will assume that when you say devide you mean divided by

first, remember that when you divide by a fraction, you invert the fraction and multiply

(2x^3)^5/3xy
-----------------
x/2y^2

becomes

(2x^3)^5/3xy times 2y^2/x

(x^a)^b=x^(ab)

(32x^15/3xy)(2y^2/x)
(32x^14/3y)(2y^2/x)
(32x^14)(2y^2)/3yx
(32x^13)(2y)/3
64x^13y/3

Answer 3

(2^5)*x^15*(2y^2)/(3xy)x

=(2^6)(x^13)y/3