Please help me with these last math problems...?

Question

1) Solve: 3y/2 = 7+y/4

2) Solve: 1/2x + 1/x = 3/8

3) Solve: x/5 = x+4/9

4) Solve: 3/x+4 - 1/x = 1/x

5) Solve 6/x+2 = 2/x-4

Answer 1

3y/2 = 7+y/4

first you need equal denominators in both fractions

6y/4 = 7 + y/4

Simplify by adding the fractions

6y/4 -y/4 = 7 + y/4 - y/4

= 5y/4 = 7

remove the fraction

5y = 28

solve for y

y = 28/5

***all of these problems can be done in the same manner, just take your time and simplfy the problem step by step***

Hope this gets you in the right direction!

Answer 2

1)6y/4-y/4=7 ==> y=28/5
3)-4x/5=4/9 ==>x= -5/9
4)1/x =-4 ==> x=-1/4
5) 2/x=-6 ==>x=-1/3
2) 3/2x= =4/9 ==>x=27/8

Answer 3

1) 3*y/2 = 7 + y/4
get all the unknowns to one side
3*y/2 - y/4 = 7
now get rid of the denominators
6*y/4 - y/4 = 5*y/4 = 7
5*y = 28
y = 28/5 ANSWER

Follow this procedure for the rest of the problems.

2) Is 1/2x =(1/2)*x or 1/(2*x)?
Indifference to parentheses leads to ambiguity. Right?

Answer 4

1)5y-28=0;
y=28/5

2)12=3x
x=4

3)4x/5=-4/9
x=-5/9

4)3/x=-4
x=3/4

5)6x-4=0
x=2/3

Answer 5

1. y= 28/5
2. x= 1/4
3. x= -5/9
4. x = -1/4
5. x= -3/2

Answer 6

1) y=28/5
2) x=4
3) x= -5/9
4) x= -1
5) x = -2/3
I hope it's wright because i did it quickly :)

Answer 7

you can only simplify these, not solve them. I hope this is helpful:)

1) 3y=14+2y/4
-14=-3y+2y/4
-14=-12y/4+2y/4
-14=-10y/4
56=10y
y=5.6

2)x/2+1/x=3/8
x^2/2x+2/2x=3/8
2+x^2=3/8
16+8x^2=3
x=(square root of)13/8

3)x=5x+20/9
-4x=20/9
-26x=20
x=-5/9

4) 3/x+4-1/x=1/x
3/x+4=0
x=-3/4

5)4/x=-6
x=-4/6
x=-2/3