Help me with this probability question, please?

Question

Help me with this question, please?
And explain/show how to get the result? :/
Thank you a bunch. <3

A five digit number is created using he digits 1-5 each once. What is the probability that the number is odd? Express your answer as a common fraction.

Thanks.

Answer 1

Whether or not the number is odd is determined by the last digit. That is equally likely to be any of 1, 2, 3, 4, or 5, so there is a 3/5 chance that the number will be odd.

Answer 2

For the number to be odd, the last digit has to be odd to (ie: 1, 3 or 5)
Lets break this down to the 3 scenarios.
1) Last digit is 1
P(last digit 1) = 1/5
2) Last digit is 3
P(last digit 3) = 1/5
3) Last digit is 5
P(last digit 5) = 1/5
Therefore,
P(number is odd) = P (last digit 1) or P (last digit 3) or P (last digit 5)
= 1/5 + 1/5 + 1/5
= 3/5