2007-08-09 14:43:53 · 6 answers · asked by lissiebobissie 2 in Science & Mathematics ➔ Mathematics
I'm not sure if this is quite what you're looking for, but x doesn't equal one specific value.
First consider: (x+3)(x-2)=0. You can see that this statement is true if x=-3 or x=2. If you mark these spots on the number line, it breaks the line up into 3 sections.
So let's look at x's inbetween -3 & 2, like x=0. If x=0, then (x+3)(x-2) = -6 < 0. This isn't what you want.
What about x < -3? Check it by testing with x = -4. Then (x+3)(x-2) = 6 > 0. Hooray!
One more area on the number line to check: x>2. Test it with x=3. So (x+3)(x-2) = 6 > 0.
In short, (x+3)(x-2)>0 is equivalent to x < -3 and x > 2
2007-08-09 15:02:21 · answer #1 · answered by jubilani 1 · 1⤊ 0⤋
The left side of the inequality is equal to zero when x equals -3 or 2. This splits the number line into 3 parts. pick a number in each section to determine when the left side of the inequality is greater than zero.
2007-08-09 14:50:32 · answer #2 · answered by Demiurge42 7 · 0⤊ 0⤋
well consider the formula as an equation to begin with
(x+3)(x-2) = 0
=> x = 2,-3
so for (x+3)(x-2) >0
=> x>2, x<-3
2007-08-09 14:55:38 · answer #3 · answered by Aslan 6 · 0⤊ 0⤋
Dang thats a hard one. Im real good at math but even I cant answer that. Sorry. Keep trying
2007-08-09 14:52:38 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I had also asked this same question three times, and not gotten a proper answer
2016-08-24 11:37:00 · answer #5 · answered by lucrecia 4 · 0⤊ 0⤋
Not sure what to say
2016-07-30 01:05:04 · answer #6 · answered by Anonymous · 0⤊ 0⤋